The mean height of 15-year-old boys (in em) is 175 and the variance is 64. For girls, the mean is 165 and the variance is 64. Assuming that the two populations are nomally distributed. If eight boys and eight girls were sampled, then the probability that the mean height of the sample of boys would be higher than the mean height of the sample of girls O 0 9878 O 0.0062 O 0.9938 O 0 9972

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The mean height of 15-year-old boys (in em) is 175 and the variance is 64. For girls, the
mean is 165 and the variance is 64. Assuming that the two populations are nomally
distributed. If eight boys and eight girls were sampled, then the probability that the mean
height of the sample of boys would be higher than the mean height of the sample of girls
18:
O 0 9878
O 0.0062
O 0.9938
0 9972
Let E[X(Y-1)] 10, E[X(Y#1)] 20, V(X)
Then E(Y)
8. V(Y) 12 and V(X+Y) 30.
O 14/5
12/5
2
Transcribed Image Text:The mean height of 15-year-old boys (in em) is 175 and the variance is 64. For girls, the mean is 165 and the variance is 64. Assuming that the two populations are nomally distributed. If eight boys and eight girls were sampled, then the probability that the mean height of the sample of boys would be higher than the mean height of the sample of girls 18: O 0 9878 O 0.0062 O 0.9938 0 9972 Let E[X(Y-1)] 10, E[X(Y#1)] 20, V(X) Then E(Y) 8. V(Y) 12 and V(X+Y) 30. O 14/5 12/5 2
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