The mean and the standard deviation of a population are 11795 and 14054 respectively. If n = 50, find 95% confidence interval for the mean. a. 7899.43 and 15690.57 b. 7989.34 and 16590.75 c. 7998.43 and 16509.75 d. 7843.99 and 15657.90 e. NONE OF THE ABOVE
The mean and the standard deviation of a population are 11795 and 14054 respectively. If n = 50, find 95% confidence interval for the mean. a. 7899.43 and 15690.57 b. 7989.34 and 16590.75 c. 7998.43 and 16509.75 d. 7843.99 and 15657.90 e. NONE OF THE ABOVE
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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![The mean and the standard deviation of a population are
11795 and 14054 respectively. If n = 50, find 95% confidence
interval for the mean.
a. 7899.43 and 15690.57
b. 7989.34 and 16590.75
c. 7998.43 and 16509.75
d. 7843.99 and 15657.90
e. NONE OF THE ABOVE](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4beeffb1-4e76-414e-906f-9b674fe10be6%2Fcc3ebd24-a25e-4d75-adf9-a2b27d14d799%2Fk4c16v6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The mean and the standard deviation of a population are
11795 and 14054 respectively. If n = 50, find 95% confidence
interval for the mean.
a. 7899.43 and 15690.57
b. 7989.34 and 16590.75
c. 7998.43 and 16509.75
d. 7843.99 and 15657.90
e. NONE OF THE ABOVE
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