The first quartile is. (Type an integer or decimal rounded to one decimal place as needed.)

MATLAB: An Introduction with Applications
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### Problem Statement

Assume that adults have IQ scores that are normally distributed with a mean of 100.2 and a standard deviation of 15.2. Find the first quartile \( Q_1 \), which is the IQ score separating the bottom 25% from the top 75%. (Hint: Draw a graph.)

---

**The first quartile is** [ ]

(Type an integer or decimal rounded to one decimal place as needed.)

### Detailed Explanation (for Educational Context)

To determine the first quartile (\( Q_1 \)) for the given normally distributed IQ scores, follow these steps:

1. **Understanding the First Quartile \( Q_1 \)**:
    - The first quartile (\( Q_1 \)) is the value below which 25% of the data falls.
    - In a standard normal distribution, this corresponds to a z-score that separates the lower 25% of the distribution from the upper 75%.

2. **Standard Normal Distribution**:
    - The standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1.
    - To find the z-score for the first quartile in a standard normal distribution, you can look up the value in a z-table or use a statistical tool.

3. **Converting to the Given Normal Distribution**:
    - For the given normal distribution with mean (\( \mu \)) = 100.2 and standard deviation (\( \sigma \)) = 15.2, we need to find the corresponding IQ score for the z-score found in step 2.

4. **Calculation Steps**:
    - Identify the z-score for \( Q_1 \) (25th percentile) using a z-table or statistical software. Typically, this z-score is approximately -0.674.
    - Use the z-score formula for a normal distribution: 
      \[
      Q_1 = \mu + (z \times \sigma)
      \]
      where:
      - \(\mu = 100.2\)
      - \(z = -0.674\)
      - \(\sigma = 15.2\)

5. **Final Calculation**:
    - Plug in the values:
      \[
      Q_1 = 100.2 + (-0.674 \times 15.2) \approx 100.2 + (-10.24) = 89.96
Transcribed Image Text:### Problem Statement Assume that adults have IQ scores that are normally distributed with a mean of 100.2 and a standard deviation of 15.2. Find the first quartile \( Q_1 \), which is the IQ score separating the bottom 25% from the top 75%. (Hint: Draw a graph.) --- **The first quartile is** [ ] (Type an integer or decimal rounded to one decimal place as needed.) ### Detailed Explanation (for Educational Context) To determine the first quartile (\( Q_1 \)) for the given normally distributed IQ scores, follow these steps: 1. **Understanding the First Quartile \( Q_1 \)**: - The first quartile (\( Q_1 \)) is the value below which 25% of the data falls. - In a standard normal distribution, this corresponds to a z-score that separates the lower 25% of the distribution from the upper 75%. 2. **Standard Normal Distribution**: - The standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1. - To find the z-score for the first quartile in a standard normal distribution, you can look up the value in a z-table or use a statistical tool. 3. **Converting to the Given Normal Distribution**: - For the given normal distribution with mean (\( \mu \)) = 100.2 and standard deviation (\( \sigma \)) = 15.2, we need to find the corresponding IQ score for the z-score found in step 2. 4. **Calculation Steps**: - Identify the z-score for \( Q_1 \) (25th percentile) using a z-table or statistical software. Typically, this z-score is approximately -0.674. - Use the z-score formula for a normal distribution: \[ Q_1 = \mu + (z \times \sigma) \] where: - \(\mu = 100.2\) - \(z = -0.674\) - \(\sigma = 15.2\) 5. **Final Calculation**: - Plug in the values: \[ Q_1 = 100.2 + (-0.674 \times 15.2) \approx 100.2 + (-10.24) = 89.96
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