The maximum patent life for a new drug is 17 years. Subtracting the length of time required by the FDA for testing and approval of the drug provides the actual patent life of the drug-that is, the length of time that a company has to recover research and development costs and make a profit. Suppose the distribution of the lengths of patent life for new drugs is as shown here. Years, x 3 4 8. 10 11 12 13 p(x) 0.03 0.07 0.07 0.12 0.18 0.18 0.16 0.10 0.05 0.03 0.01 (a) Find the expected number of years of patent life for a new drug. (b) Find the standard deviation of x. (Round your answer to four decimal places.) (c) Find the probability that x falls into the interval u ± 20.
The maximum patent life for a new drug is 17 years. Subtracting the length of time required by the FDA for testing and approval of the drug provides the actual patent life of the drug-that is, the length of time that a company has to recover research and development costs and make a profit. Suppose the distribution of the lengths of patent life for new drugs is as shown here. Years, x 3 4 8. 10 11 12 13 p(x) 0.03 0.07 0.07 0.12 0.18 0.18 0.16 0.10 0.05 0.03 0.01 (a) Find the expected number of years of patent life for a new drug. (b) Find the standard deviation of x. (Round your answer to four decimal places.) (c) Find the probability that x falls into the interval u ± 20.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![### Distribution of Patent Life for New Drugs
The maximum patent life for a new drug is 17 years. Subtracting the length of time required by the FDA for testing and approval of the drug provides the actual patent life of the drug—that is, the length of time that a company has to recover research and development costs and make a profit. Suppose the distribution of the lengths of patent life for new drugs is as shown below:
| Years, \( x \) | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 |
|-----------------|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|
| \( p(x) \) | 0.03| 0.07| 0.07| 0.12| 0.18| 0.18| 0.16| 0.10| 0.05| 0.03| 0.01|
### Tasks
(a) **Find the expected number of years of patent life for a new drug.**
[Text box for answer]
(b) **Find the standard deviation of \( x \). (Round your answer to four decimal places.)**
[Text box for answer]
(c) **Find the probability that \( x \) falls into the interval \( \mu \pm 2\sigma \).**
[Text box for answer]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3fdf87a1-6c5c-465d-8ddf-eaf69800c0eb%2F599962cb-150c-4150-9fb6-58d2b93a5a13%2F3ws4bf55_processed.png&w=3840&q=75)
Transcribed Image Text:### Distribution of Patent Life for New Drugs
The maximum patent life for a new drug is 17 years. Subtracting the length of time required by the FDA for testing and approval of the drug provides the actual patent life of the drug—that is, the length of time that a company has to recover research and development costs and make a profit. Suppose the distribution of the lengths of patent life for new drugs is as shown below:
| Years, \( x \) | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 |
|-----------------|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|
| \( p(x) \) | 0.03| 0.07| 0.07| 0.12| 0.18| 0.18| 0.16| 0.10| 0.05| 0.03| 0.01|
### Tasks
(a) **Find the expected number of years of patent life for a new drug.**
[Text box for answer]
(b) **Find the standard deviation of \( x \). (Round your answer to four decimal places.)**
[Text box for answer]
(c) **Find the probability that \( x \) falls into the interval \( \mu \pm 2\sigma \).**
[Text box for answer]
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