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- The Toylot company makes an electric train with a motor that it claims will draw an average of no more than 0.8 amps under a normal load. A sample of nine motors were tested, and it was found that the mean current was x = 1.32 amps, with a sample standard deviation of s = 0.44 amps. Perform a statistical test of the Toylot claim. (Use a 1% level of significance.)What are we testing in this problem? single meansingle proportion What is the level of significance?State the null and alternate hypotheses. H0: p = 0.8; H1: p ≠ 0.8H0: p ≤ 0.8; H1: p > 0.8 H0: ? ≤ 0.8; H1: ? > 0.8H0: ? ≠ 0.8; H1: ? = 0.8H0: p ≠ 0.8; H1: p = 0.8H0: ? = 0.8; H1: ? ≠ 0.8 What sampling distribution will you use? What assumptions are you making? The standard normal, since we assume that x has a normal distribution with known ?.The Student's t, since we assume that x has a normal distribution with known ?. The standard normal, since we assume that x has a normal distribution with unknown ?.The…Q.28 onlyA random sample of 89 tourists in British Columbia showed that they spent an average of $2860 (in a week) with an assumed population standard deviation of $126; and a sample of 64 tourists in Alberta showed that they spent an average of $2935 (in a week) with an assumed population standard deviation of $138. We are interested in determining if there is any significant difference between the average expenditures of all the tourists who visited the two provinces.a. At a significance level of 0.05, are the two average expenditures significantly different? b. Calculate the 99% confidence interval and interpret your results?
- This test statistic leads to a decision to... A.) reject the null B.) accept the null C.) fail to reject the null You wish to test the following claim (Ha) at a significance level of α=0.002α=0.002. Ho:μ=55.6 Ha:μ>55.6You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=601n=601 with mean ¯x=57.1x¯=57.1 and a standard deviation of s=19.9s=19.9.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = ___________What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = ____________The p-value is... A.) less than (or equal to) αα B.) greater than α As such, the final conclusion is that... A.) There is sufficient evidence to warrant rejection of the claim that the population mean is greater than 55.6. B.) There is not sufficient evidence to warrant rejection of the claim that the population mean is greater than…"On the Standford-Binet test, the mean IQ is 100. A class of 13 kindergarten pupils were tested with a resulting mean of 94 and a standard deviation of 4.65. Does this group have a mean significantly different than the norm group? Use 0.01 as your level of significance. What are the given information? population mean:Blank 1 sample size:Blank 2 sample mean:Blank 3 sample standard deviation:Blank 4 level of significance:Blank 5 degrees of freedom: Blank 6 What are the critical values? Write the positive first then the negative t:Blank 7 andBlank 8 What is the value of the calculated t? Round your answer to the nearest hundredths. t:Blank 9"A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. a. Use a 0.01 significance level to test the claim that men have a higher mean body temperature than women. What are the null and alternative hypotheses? A. Ho: M₁ = ₂ H₁: H₁ H₂ C. Ho: M₁ = H2 H₁: H₁ H₂ The test statistic, t, is (Round to two decimal places as needed.) B. Ho: H₁ H₂ H₁ H₁Need asap 19. A vendo machine is designed to fill plastic cups with 19 ounces of orange juice. A costumer suspects that the machine is not filling the plastic cups completely. A sample of 35 cups has a mean of 18.7 ounces and a standard deviation 0.9 ounce. Is there enough evidence to support the consumer’s claim at α=0.01? What is the value of the statistical test? A. 2.97B. -2.97C. -1.97D. 1.9720. In t – test, if the population standard deviation is unknown what is used to replace the population standard deviation?A. sample sizeB. population varianceC. sample standard deviationD. hypothesis standard deviation21. Which of the following does not describe a null hypothesis?A. It is denoted by HoB. It has a statement of equalityC. It is the hypothesis to be testedD. It states a specific difference between a parameter and statistics22. A group of researchers wants to test the truth in the company’s claim that the travel time from Manila…5.37 Dental anxiety study. To gauge their fear of going to a den- tist, a random sample of adults completed the Modified Dental Anxiety Scale questionnaire (BMC Oral Health, Vol. 9, 2009). Scores on the scale range from zero (no anx- iety) to 25 (extreme anxiety). The mean score was 11 and the standard deviation was 4. Assume that the distribution of all scores on the Modified Dental Anxiety Scale is ap- proximately normal with µ = 11 and o = 4. a. Suppose you score a 10 on the Modified Dental Anxiety Scale. Find the z-value for your score. b. Find the probability that someone scores between 10 and 15 on the Modified Dental Anxiety Scale. c. Find the probability that someone scores above 20 on the Modified Dental Anxiety Scale.The mean annual tuition and fees for a sample of 14 private colleges in California was $37,900 witrh a standard deviation of $7,200. A dotplot shows that it is reasonable to assume that the population is approxiamately normal. Can you conclude that the mean tuition and fees for private institutions in California differs from $35,000? a. State the null and alternate hypothesis. b. Compute the value of the t statistic. How many degrees of fredom are there?Suppose you are interested in testing whether average monthly gasoline expenditure differs from $50 at the 5% significance level. You take a sample of 30 and calculate a sample mean of 51 and sample standard deviation of 12. Given this information the null and alternative hypotheses are as follows: H0: μ=50 H1: μ≠50 What is the p-value for this test? (Round to four decimal places. )A report states that the mean yearly salary offer for students graduating with a degree in accounting is $48,722. Suppose that a random sample of 50 accounting graduates at a large university who received job offers resulted in a mean offer of $49,870 and a standard deviation of $3900. Do the sample data provide strong support for the claim that the mean salary offer for accounting graduates of this university is higher than the national average of $48,7227 Ho: = Ha: Select an answer V (Put in the correct symbol and value) a = P-value =In a test of hypothesis, the null hypothesis is that the population mean is equal to 90 and the alternative hypothesis is that the population mean is not equal to 90. A sample of 16 elements selected from this population produced a mean of 86.75 and a standard deviation of 12.54. The significance level is 2%. a. –2.602 and 2.602 b. –2.583 and 2.583 c. –2.131 and 2.131 d. –1.341 and 1.341SEE MORE QUESTIONS