A simple random sample of 25 math students resulted in a mean IQ of 113.5 with a standard deviation of 12.5 Use a 0.05 significance level to test a claim that math students have a mean IQ greater than 110. [Note: Assume the population standard deviation is unknown.] a. Clearly identify and state the null hynothesis Ho and tho
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- Listed in the data table are IQ scores for a random sample of subjects with medium lead levels in their blood. Also listed are statistics from a study done of IQ scores for a random sample of subjects with high lead levels. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. a. Use a 0.05 significance level to test the claim that the mean IQ scores for subjects with medium lead levels is higher than the mean for subjects with high lead levels. What are the null and alternative hypotheses? Assume that population 1 consists of subjects with medium lead levels and population 2 consists of subjects with high lead levels. OA. Ho: H₁ H2 H₁: H₁ H₂ C. Ho: H₁ H₂ H₁: H₁ H₂ The test statistic is C (Round to two decimal places as needed.) OB. Ho: H1 H₂ H₁: H₁ H₂ OD. Ho: H₁ H₁ H₁ IQ Scores H₂ H₂ Medium Lead Level High Lead Level 72 n₂ = 11…Listed in the data table are IQ scores for a random sample of subjects with medium lead levels in their blood. Also listed are statistics from a study done of IQ scores for a random sample of subjects with high lead levels. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. a. Use a 0.05 significance level to test the claim that the mean IQ scores for subjects with medium lead levels is higher than the mean for subjects with high lead levels. What are the null and alternative hypotheses? Assume that population 1 consists of subjects with medium lead levels and population 2 consists of subjects with high lead levels. OA. Ho: H₁ H₂ H₁: Hy > H₂ OC. Ho: H₁ H₂ H₁: Hy > H₂ The test statistic is The P-value is (Round to two decimal places as needed.) (Round to three decimal places as needed.) C State the conclusion for the test. B.…Consider a dataset containing the heights of 38 females who said they prefer to sit in the front of the classroom yields a sample average of 62 inches and a sample standard deviation of 2.5 inches. Suppose that the average height for the general population of college females is 65 inches. An analyst wants to test the claim that the true average height of females who prefer to sit in the front of the classroom is lower than it is for the general population. In the hypothesis for the above claim (at significance level of 10%), the appropriate test, test statistic (name and value), and pvalue is the approximate Z-test with z-statistic = 62 and pvalue = 0. the approximate Z-test with z-statistic = 7.40 and pvalue not calculable because normality is not given. = 0. the approximate Z-test with z-statistic = -7.40 and pvalue = 0.
- A random sample of 43 subjects who identified themselves as compulsive buyers was obtained and given a questionnaire. They had a mean questionnaire score of 0.52 with a standard deviation of 0.17. Test the claim that the population of self-identified compulsive buyers has a mean greater than the mean of 0.51 for the general population. Use a 0.05 significance level. State the null and alternative hypotheses. O B. Ho H= 0.51 O A. H, p= 0.51 H3 p> 0.51 H3 µ#0.51 ОС. Но н0.51 H3 p= 0.51 O D. Ho H=051 H, p<0,51Q.28 onlyA report states that the mean yearly salary offer for students graduating with a degree in accounting is $48,722. Suppose that a random sample of 50 accounting graduates at a large university who received job offers resulted in a mean offer of $49,870 and a standard deviation of $3900. Do the sample data provide strong support for the claim that the mean salary offer for accounting graduates of this university is higher than the national average of $48,722? Ho: μ = Ha: (Put in the correct symbol and value) ✓ Select an answer a not = P-value: = ↑ Based on the above we choose to Select an answer Question Help: Post to forum Submit Question
- Need asap 19. A vendo machine is designed to fill plastic cups with 19 ounces of orange juice. A costumer suspects that the machine is not filling the plastic cups completely. A sample of 35 cups has a mean of 18.7 ounces and a standard deviation 0.9 ounce. Is there enough evidence to support the consumer’s claim at α=0.01? What is the value of the statistical test? A. 2.97B. -2.97C. -1.97D. 1.9720. In t – test, if the population standard deviation is unknown what is used to replace the population standard deviation?A. sample sizeB. population varianceC. sample standard deviationD. hypothesis standard deviation21. Which of the following does not describe a null hypothesis?A. It is denoted by HoB. It has a statement of equalityC. It is the hypothesis to be testedD. It states a specific difference between a parameter and statistics22. A group of researchers wants to test the truth in the company’s claim that the travel time from Manila…Kurtis is a statistician who claims that the average salary of an employee in the city of Yarmouth is no more than $55,000 per year. Gina, his colleague, believes this to be incorrect, so she randomly selects 61 employees who work in Yarmouth and record their annual salary. Gina calculates the sample mean income to be $56,500 per year with a sample standard deviation of 3,750. Using the alternative hypothesis H1 : 55.0 appropriate hypothesis test. Round the test statistic to two decimal places and the p-value to three decimal places. Right-Tailed T-Table probability Degrees of Freedom 54 0.00040.00140.00240.00340.00440.00540.0064 56 57 58 59 60 3.562 3.135 2.943 2.816 2.719 2.641 2.576 3.558 3.132 2.941 2.814 2.7172.640 2.574 3.554 3.130 2.939 2.8122.716 2.638 2.572 3.550 3.127 2.937 2.810 2.714 2.636 2.571 3.547 3.125 2.935 2.8082.712 2.635 2.569 3.544 3.122 2.933 2.806 2.711 2.633 2.568 3.540 3.120 2.931 2.805 2.709 2.632 2.567 Provide your answer below , p-value -5.37 Dental anxiety study. To gauge their fear of going to a den- tist, a random sample of adults completed the Modified Dental Anxiety Scale questionnaire (BMC Oral Health, Vol. 9, 2009). Scores on the scale range from zero (no anx- iety) to 25 (extreme anxiety). The mean score was 11 and the standard deviation was 4. Assume that the distribution of all scores on the Modified Dental Anxiety Scale is ap- proximately normal with µ = 11 and o = 4. a. Suppose you score a 10 on the Modified Dental Anxiety Scale. Find the z-value for your score. b. Find the probability that someone scores between 10 and 15 on the Modified Dental Anxiety Scale. c. Find the probability that someone scores above 20 on the Modified Dental Anxiety Scale.
- The mean annual tuition and fees for a sample of 14 private colleges in California was $37,900 witrh a standard deviation of $7,200. A dotplot shows that it is reasonable to assume that the population is approxiamately normal. Can you conclude that the mean tuition and fees for private institutions in California differs from $35,000? a. State the null and alternate hypothesis. b. Compute the value of the t statistic. How many degrees of fredom are there?Listed in the data table are IQ scores for a random sample of subjects with medium lead levels in their blood. Also listed are statistics from a study done of IQ scores for a random sample of subjects with high lead levels. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. a. Use a 0.01 significance level to test the claim that the mean IQ scores for subjects with medium lead levels is higher than the mean for subjects with high lead levels. What are the null and alternative hypotheses? Assume that population 1 consists of subjects with medium lead levels and population 2 consists of subjects with high lead levels. OA. Ho: H₁1 H₂ H₁ H₁ H₂ OC. Ho: H₁ H₂ H₁: H₁ H₂ The test statistic is 0.20. (Round to two decimal places as needed.) The P-value is 0.423. (Round to three decimal places as needed.) State the conclusion for the…A 0.05 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is greater than 0.5. Assume that sample data consists of 78 girls in 144 births, so the sample statistic of 1324 results in a z score that is 1 standard deviation above 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.Part 4d. Is the test two-tailed, left-tailed, or right-tailed? Left-tailed Right-tailed Two-tailedPart 5e. What is the value of the test statistic?The test statistic is enter your response here. (Type an integer or a decimal.)Part 6f. What is the P-value?The P-value is enter your response here. (Round to four decimal places as needed.)