(a-2) State the conclusion.a. tcalc = −1.760. There is significant evidence to reject the manufacturer's claim.b. tcalc = -1.760. There is not enough evidence to reject the manufacturer's claim.aOb The manufacturer of an airport baggage scanning machine claims it can handle an average of 560 bags per hour.(a-1) At a = .05 in a left-tailed test, would a sample of 16 randomly chosen hours with a mean of 538 and a standard deviation of 50indicate that the manufacturer's claim is overstated? Choose the appropriate hypothesis.a. H₁:<560. Reject H₁ if tcalc> -1.753b. He:<560. Reject He if tcalc > -1.753c. H₁:2 560. Reject H₁ if tcalc < -1.753d. He: 2 560. Reject He if tcalc < -1.753OcO aObOd

Given information:- Mean = 538, S.D = 50 n = 16 μ=560, α=0.05 Hypothesis is left tailed test.

Answered: The manufacturer of an airport baggage…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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V. MN * 00 In a random sample of 10 cell phones, the mean full retail price was $533.20 and the standard deviation was $194.00, Further research suggests that the population mean is $431.82. Does the t-value for the original sample fall between - to 9g and to og? Assume that the population of full retail prices for cell phones is normally distributed. The t-value of t= fall between - to 99 and to 99 because to 99 = 66 66 (Round to two decimal places as needed.) Next 11:34 AM 58°F Sunny ^ 11/23/2021 同に F10 PrtSc F8 F11 F12 8. 9. B.
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In a sample of 14 randomly selected high school seniors, the mean score on a standardized test was 1184 and the standard deviation was 162.8. Further research suggests that the population mean score on this test for high school seniors is 1014. Does the t-value for the original sample fall between - to 99 and to 99? Assume that the population of test scores for high school seniors is normally distributed. The t-value of t = fall between to.99 and to.99 because to.99 %3D (Round to two decimal places as needed.)
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75 specimens of the new chip were tested and 67 specimens of the old chip were tested. The average speed, in MHz, for the new chips was 494.9 and the standard deviation was 19.3. The average speed of the old chips was 485.8 and the standard deviation was 16.7. Suppose we wish to test Ho : Hx - Hy = 0 versus H1 : Hx - Hy # 0. Calculate the z-score. (answers are considered correct if they're within 5% of the correct value)
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