Analyzing Infrared Spectra
The electromagnetic radiation or frequency is classified into radio-waves, micro-waves, infrared, visible, ultraviolet, X-rays and gamma rays. The infrared spectra emission refers to the portion between the visible and the microwave areas of electromagnetic spectrum. This spectral area is usually divided into three parts, near infrared (14,290 – 4000 cm-1), mid infrared (4000 – 400 cm-1), and far infrared (700 – 200 cm-1), respectively. The number set is the number of the wave (cm-1).
IR Spectrum Of Cyclohexanone
It is the analysis of the structure of cyclohexaone using IR data interpretation.
IR Spectrum Of Anisole
Interpretation of anisole using IR spectrum obtained from IR analysis.
IR Spectroscopy
Infrared (IR) or vibrational spectroscopy is a method used for analyzing the particle's vibratory transformations. This is one of the very popular spectroscopic approaches employed by inorganic as well as organic laboratories because it is helpful in evaluating and distinguishing the frameworks of the molecules. The infra-red spectroscopy process or procedure is carried out using a tool called an infrared spectrometer to obtain an infrared spectral (or spectrophotometer).
![**Problem Statement:**
Determine the major product of the following reaction:
\[
\text{Benzene with a triple bond at the end} + \text{NaNH}_2 \rightarrow ? + \text{NH}_3
\]
**Options:**
**a)** A benzene ring with a sodium anion (Na⁺) attached to the triple-bonded carbon in a linear configuration.
**b)** A benzene ring with a sodium anion (Na⁺) attached to an internal carbon forming a cyclic structure with a bridged nitrogen.
**c)** A benzene ring with a nitrogen anion (N⁻) at the end of the triple bond.
**d)** A benzene ring with two sodium ions (Na⁺) attached to two adjacent carbons, forming a charged cyclic structure.
**e)** A benzene ring with a triple bond extension, having a sodium anion (Na⁺) at the end carbon.
In this reaction, sodium amide (NaNH₂) acts as a base, facilitating the removal of a proton to form the corresponding anion that serves as an intermediate. The major product is determined by the stability and favorability of the resulting anions or structures.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F20b515c9-5e3a-448e-90a2-ac3b562e1523%2F037ddd47-0430-4dab-b82e-e68574b8ea7b%2Fmrqygk_processed.jpeg&w=3840&q=75)
The acidic of terminal hydrogen in hydrocarbons increases in this order:
Alkane < alkene < alkyne
Terminal hydrogen of alkyne is most acidic because of the sp-hybridisation of terminal carbon of alkyne.
Terminal hydrogen of alkyne is highly acidic and that's why it reacts with sodamide to form sodium alkynide.
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