Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Elimination Reaction Quiz
**Question:**
What is the major product for the following elimination reaction?
**Reaction:**
\[ \begin{array}{c@{}c@{}c}
& \underset{\text{(HBr)}}{\ce{\longrightarrow}} & {} \\[-0.5em]
\ce{H3C \;-\; CH \;=\; CH \;-\; CH3 \;-\; CH3 \;OH} & \underset{\text{(H2O)}}{\overset{\text{HBr}}{\longrightarrow}} & \\
\end{array} \]
**Options:**
\[
\begin{array}{c}
\text{A.} \quad \ce{H3C \;-\; CH \;=\; CH \;-\; CH3 \;-\; CH3} \; \text{Br} \\
\text{B.} \quad \ce{H3C \;-\; CH \;=\; CH \;-\; CH \;-\; CH3 \;-\; CH3} \\
\text{C.} \quad \ce{H3C \;-\; CH \;=\; CH \;-\; CH2 \;-\; CH3 \;-\; CH2} \\
\text{D.} \quad \ce{H3C \;-\; CH \;=\; CH- \;-\; CH3 \;-\; CH3}
\end{array}
\]
**Choices:**
- ⃝ C
- ⃝ A
- ⃝ B
- ⃝ D
**Instruction:** Select the option that indicates the major product formed during the elimination reaction with the given reagents.
---
**Explanation:**
In an elimination reaction using HBr (hydrobromic acid) in the presence of H\(_2\)O (water), the major product is generally an alkene formed via the loss of a bromide ion (Br\(^-\)) and a hydrogen ion (H\(^+\)). The product is determined by the Zaitsev's rule which states that the more substituted alkene (having more alkyl groups attached to the double-bonded carbons) will be the major product due to its greater stability.
Review the structure of each given option to determine which one](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb7a6ddd6-9522-4c7e-bff1-23d6943042e2%2F6991f9cf-2879-46ea-9cde-adfa22fd620b%2Fj159pgl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Elimination Reaction Quiz
**Question:**
What is the major product for the following elimination reaction?
**Reaction:**
\[ \begin{array}{c@{}c@{}c}
& \underset{\text{(HBr)}}{\ce{\longrightarrow}} & {} \\[-0.5em]
\ce{H3C \;-\; CH \;=\; CH \;-\; CH3 \;-\; CH3 \;OH} & \underset{\text{(H2O)}}{\overset{\text{HBr}}{\longrightarrow}} & \\
\end{array} \]
**Options:**
\[
\begin{array}{c}
\text{A.} \quad \ce{H3C \;-\; CH \;=\; CH \;-\; CH3 \;-\; CH3} \; \text{Br} \\
\text{B.} \quad \ce{H3C \;-\; CH \;=\; CH \;-\; CH \;-\; CH3 \;-\; CH3} \\
\text{C.} \quad \ce{H3C \;-\; CH \;=\; CH \;-\; CH2 \;-\; CH3 \;-\; CH2} \\
\text{D.} \quad \ce{H3C \;-\; CH \;=\; CH- \;-\; CH3 \;-\; CH3}
\end{array}
\]
**Choices:**
- ⃝ C
- ⃝ A
- ⃝ B
- ⃝ D
**Instruction:** Select the option that indicates the major product formed during the elimination reaction with the given reagents.
---
**Explanation:**
In an elimination reaction using HBr (hydrobromic acid) in the presence of H\(_2\)O (water), the major product is generally an alkene formed via the loss of a bromide ion (Br\(^-\)) and a hydrogen ion (H\(^+\)). The product is determined by the Zaitsev's rule which states that the more substituted alkene (having more alkyl groups attached to the double-bonded carbons) will be the major product due to its greater stability.
Review the structure of each given option to determine which one
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