The Lucas numbers are a series of numbers where the first two Lucas numbers (i.e., at indices 0 and 1) are 2 and 1 (respectively) and the kth Lucas number L_k (where k>1) is L_(k-1) + L_(k-2). Consider the following recursive definition for a function that is supposed to find the nth element of the Lucas numbers. Select the best option that identifies the line of code that prevents this function from running recursively and provides the correct code. Question options:   line 5 should be return recursive_function(n-1) + recursive_function(n-2)   line 3 should be return [2,1][n-1][n-2]   line 3 should be return [2,1][n-1]   line 2 should be if n <= 2:   line 5 should be return recursive_function(n-1 + n-2)   None of these options

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter15: Recursion
Section: Chapter Questions
Problem 20SA
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The Lucas numbers are a series of numbers where the first two Lucas numbers (i.e., at indices 0 and 1) are 2 and 1 (respectively) and the kth Lucas number L_k (where k>1) is L_(k-1) + L_(k-2). Consider the following recursive definition for a function that is supposed to find the nth element of the Lucas numbers. Select the best option that identifies the line of code that prevents this function from running recursively and provides the correct code.

Question options:

 
line 5 should be return recursive_function(n-1) + recursive_function(n-2)
 
line 3 should be return [2,1][n-1][n-2]
 
line 3 should be return [2,1][n-1]
 
line 2 should be if n <= 2:
 
line 5 should be return recursive_function(n-1 + n-2)
 
None of these options
line 1. def recursive_function(n):
line 2.
line 3.
line 4.
line 5.
if n < 2:
return [2,1][n]
else:
return recursive function(n+1) + recursive function(n+2)
Transcribed Image Text:line 1. def recursive_function(n): line 2. line 3. line 4. line 5. if n < 2: return [2,1][n] else: return recursive function(n+1) + recursive function(n+2)
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