Question 1: Tracing Recursive functions The solution can be handwritten in a paper and attach the pictures of solution to a PDF file a) Trace the following recursive method for the function call "multiply Digits (58741)" and show the output result public static int multiplyDigits(int n) { if (n == 0) return 1; else return ((n % 10) * multiplyDigits (n / 10)); } b) Trace the following recursive method for the function call "fibCalc(5,0,1)" and show the output. public static int fibCalc(int n, int s, int t) { 0) return s; 1) return t; return fibCalc(n - 1, t, s + t); if (n if (n == ==

Question 1: Tracing Recursive functions The solution can be handwritten in a paper and attach the pictures of solution to a PDF file a) Trace the following recursive method for the function call "multiply Digits (58741)" and show the output result public static int multiplyDigits(int n) { if (n == 0) return 1; else return ((n % 10) * multiplyDigits (n / 10)); } b) Trace the following recursive method for the function call "fibCalc(5,0,1)" and show the output. public static int fibCalc(int n, int s, int t) { 0) return s; 1) return t; return fibCalc(n - 1, t, s + t); if (n if (n == ==

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Using Python Recursion is the concept of a function calling itself until the problem is solved when the Base Case is met. Study Recursion: See slides in Modules, Practice Slides, lab12 and also Recursion is in chapter 9 of the textbook. Some examples of recursion are: compute [ factorial of a number, towers of Hanoi, fractals (as shown in the textbook), and many more]. Example: See slides Page 2 For this assignment we'll use Collatz Cojecture (see Wikipedia). Collatz Conjecture algorithm: Given a number n, first call to the function: f(n): In the function: if n == 1 return 1: if n is even then f(n/2), i.e. call self with the new value. else (n is odd) call self with the new value, f((n*3)+1) and repeat. All numbers eventually end up with 1. The program should test for the base case which is: if n == 1, in which case it returns to the caller with 1. This problem is perfect to demonstrate Recursion.Create a list with random numbers (you can just do this part manually) in the list as 1,…
K + edgenuity.com/player/ s Semester A 7 1 2 3 4 5 05 return 1 else: return n* factorial(n-1) Which line of code includes a recursive function call? 0 3 04 01 Consider the Python code for finding the factorial of an integer n using recursion. Line numbers have been added to the left of each line of code. def factorial(n): if n == 1: Mark this and return c C O M 31 0 DELL O FIXIXI A Save and Exit G < Next English Sign out V 4 19 Kinley Heat TIME REMAINING 59:14 Submit Mar 27 0 2:38
Ex. 01 : Recursion About So far, we have learned that we can perform repetitive tasks using loops. However, another way is by creating methods that call themselves. This programming technique is called recursion and, a method that calls itself within it's own body is called a recursive method. One use of recursion is to perform repetitive tasks instead of using loops, since some problems seem to be solved more naturally with recursion than with loops. To solve a problem using recursion, it is broken down into sub-problems. Each sub-problem is similar to the original problem, but smaller in size. You can apply the same approach to each sub-problem to solve it recursively. All recursive methods use conditional tests to either 1. stop or 2. continue the recursion. Each recursive method has the following characteristics: 1. end/terminating case: One or more end cases to stop the recursion. 2. recursive case: reduces the problem in to smaller sub-problems, until it reaches (becomes) the end…
4. CodeW. X b For fun X Solved x b Answer x+ Ohttps://codeworko... CodeWorkout X264: Recursion Programming Exercise: Multiply For function multiply,write the missing base case condition and action. This function will multiply two numbers x and y.You can assume that both x and y are positive. Examples: multiply(2, 3) -> 6 Your Answer: 1 public int multiply(int x, int y) { 2. if > { > } else { return multiply(x 1, y) + y; 3. 5. { 7. 1:08 AM 50°F Clear 日

Write the definition of a recursive function int simpleSqrt(int n) The function returns the integer square root of n, meaning the biggest integer whose square is less than or equal to n. You may assume that the function is always called with a nonnegative value for n. Use the following algorithm: If n is 0 then return 0. Otherwise, call the function recursively with n-1 as the argument to get a number t. Check whether or not t+1 squared is strictly greater than n. Based on that test, return the correct result. For example, a call to simpleSqrt(8) would recursively call simpleSqrt(7) and get back 2 as the answer. Then we would square (2+1) = 3 to get 9. Since 9 is bigger than 8, we know that 3 is too big, so return 2 in this case. On the other hand a call to simpleSqrt(9) would recursively call simpleSqrt(8) and get back 2 as the answer. Again we would square (2+1) = 3 to get back 9. So 3 is the correct return value in this case.
Compute the sum of all elements of an array1. Describe the definition of recursive function Base case(s) Recursive case(s) 2. Write the code.
Python Using recursion only No loops Note that in a correct solution the isdigit method or in operator will never be applied to the entire string s. The function must return and not print the resulting string. def getDigits(s):
Make a code using Recursion The countSubstring function will take two strings as parameters and will return an integer that is the count of how many times the substring (the second parameter) appears in the first string without overlapping with itself. This method will be case insensitive. For example: countSubstring(“catwoman loves cats”, “cat”) would return 2 countSubstring(“aaa nice”, “aa”) would return 1 because “aa” only appears once without overlapping itself. public static int countSubstring(String s, String x) { if (s.length() == 0 || x.length() == 0) return 1; if (s.length() == 1 || x.length() == 1){ if (s.substring(0,1).equals(x.substring(0,1))){ s.replaceFirst((x), " "); return 1 + countSubstring(s.substring(1), x); } else { return 0 + countSubstring(s.substring(1), x); } } return countSubstring(s.substring(0,1), x) + countSubstring(s.substring(1), x); } public class Main { public static void main(String[] args) {…
Compute the combinations of n things taken k at a time using both iterative and recursive methods. Both methods should use only int types for mathematical operations. If the iterative method continues to mock, that is fine, the recursive method should not. Can you please modify the following code for the given question?(Java Programming) public class Combination { private static boolean useFact; /*** Computes some combinations.* * @param args unused*/public static void main(String[] args) {for (int i = 0; i < 2; i++) {useFact = (i % 2 == 0);System.out.println(useFact ? "FACTORIAL METHOD" : "RECURSIVE METHOD");System.out.println();combination(2, 2);combination(3, 2);combination(4, 3);combination(10, 2);combination(52, 5);combination(60, 4);combination(75, 3);combination(100, 4);System.out.println();}} /*** A method which switches between the two combination methods* @param n the number of things* @param k how many to choose*/public static void combination(int n, int k)…
Python code
Write code to complete raise_to_power(). Note: This example is for practicing recursion; a non-recursive function, or using the built-in function math.pow(), would be more common.Sample output with inputs: 4 24^2 = 16 def raise_to_power(base_val, exponent_val): if exponent_val == 0: result_val = 1 else: result_val = base_val * ''' Your solution goes here ''' return result_val user_base = int(input())user_exponent = int(input()) print('{}^{} = {}'.format(user_base, user_exponent, raise_to_power(user_base, user_exponent)))
Which is the base case of the following recursion function: def mult3(n): if n == 1: return 3 else: return mult3(n-1) + 3 else n == 1 mult3(n) return mult3(n-1) + 3