The lowest triplet state in naphthalene (C10H8) is about 11,000 cm-1 below the lowest excited singlet electronic level at 77 K. Calculate the ratio of populations in these two states at equilibrium. [Hint: The Boltzmann equation is given by N2/N1 = (92/91)exp(-AE/KBT), where g₁ and 92 are the degeneracies for levels 1 and 2.] N₂ N1
The lowest triplet state in naphthalene (C10H8) is about 11,000 cm-1 below the lowest excited singlet electronic level at 77 K. Calculate the ratio of populations in these two states at equilibrium. [Hint: The Boltzmann equation is given by N2/N1 = (92/91)exp(-AE/KBT), where g₁ and 92 are the degeneracies for levels 1 and 2.] N₂ N1
Chemistry
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Chapter1: Chemical Foundations
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![The lowest triplet state in naphthalene (C10H8) is about 11,000 cm-1 below the lowest excited singlet electronic level at 77 K.
Calculate the ratio of populations in these two states at equilibrium. [Hint: The Boltzmann equation is given by
N2/N1 = (92/91)exp(-AE/KBT), where g₁ and 92 are the degeneracies for levels 1 and 2.]
N₂
N1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbdb9959e-e33a-4a68-ad26-ee9888f60b9f%2F9ae1a31c-f11b-49bf-b59b-349a485b3e4c%2Fzini0t_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The lowest triplet state in naphthalene (C10H8) is about 11,000 cm-1 below the lowest excited singlet electronic level at 77 K.
Calculate the ratio of populations in these two states at equilibrium. [Hint: The Boltzmann equation is given by
N2/N1 = (92/91)exp(-AE/KBT), where g₁ and 92 are the degeneracies for levels 1 and 2.]
N₂
N1
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