The low pressure pyrolysis of nitroethane takes place according to a first-order reaction: C,H;NO2(g) C,H¼(g) +HNO,(g) The activation energy is Ea = 180 kJ mol". At 494°C, the reaction rate constant is 0.313 s. (a) Calculate the Arrhenius factor A for this reaction. (b) Calculate the rate constant for this reaction at 394°C. Submit Answer Retry Entire Group 7 more group attempts remaining

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I don’t know how to do this question using the Arrhenius Equation and rate constant.
Use the References to access important values if needed for this question.
The low pressure pyrolysis of nitroethane takes place according to a first-order reaction:
C,H;NO2(g) C¿H4(g) +HNO,(g)
The activation energy is Ea = 180 kJ mol"!. At 494°C, the reaction rate constant is 0.313 s-1.
(a) Calculate the Arrhenius factor A for this reaction.
(b) Calculate the rate constant for this reaction at 394°C.
s-1
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Transcribed Image Text:Use the References to access important values if needed for this question. The low pressure pyrolysis of nitroethane takes place according to a first-order reaction: C,H;NO2(g) C¿H4(g) +HNO,(g) The activation energy is Ea = 180 kJ mol"!. At 494°C, the reaction rate constant is 0.313 s-1. (a) Calculate the Arrhenius factor A for this reaction. (b) Calculate the rate constant for this reaction at 394°C. s-1 Submit Answer Retry Entire Group 7 more group attempts remaining Previous Next Email Instructor Save Cengage Learning | Cengage Technical Support DII DD F3 F4 F5 F6 F7 F8 F9 F10 F11 F12 2$ & ( ) + 4 7 8. Y { } [ F G H J K .. .- くo ト
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