The local baseball team conducts a study to find the amount spent on refreshments at the ball park. Over the course of the seasonthey gather simple random samples of 500 men and 1000 women. For men, the average expenditure was $20, with a standarddeviation of $3. For women, it was $15, with a standard deviation of $2.What is the 99% confidence interval for the spending difference between men and women? Assume that the two populations areindependent and normally distributed. Use 3 decimal places.Lower limit =Upper limit =

Answered: Image /qna-images/answer/47447b34-f853-4ef0-9eb9-f05874369484.jpg

Answered: The local baseball team conducts a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose we want a 99% confidence interval for the average amount spent on books by freshmen in their first year at college. The amount spent has a normal distribution with standard deviation $31. How large should the sample be if the margin of error is to be less than $3?
A published study says that 95 percent of American children are vaccinated against measles, with a standard deviation of 1.5 percent. You draw a sample of 100 children from your community and check their vaccination records, to see if the vaccination rate in your community is the same as the nationalaverage. What distribution will you use for this test, and why?
In a study, 110 children of a certain race in a certain city were randomly assigned to one of two groups: one group enrolled in a preschool, and the other group did not. A research question was whether attendance at preschool had an effect on high school graduation. The accompanying table shows whether the students graduated from regular high school or not and includes both boys and girls. Find a 95% confidence interval for the difference in proportions, and interpret it. Click the icon to view the data. Step 1: Calculate percentages Looking at children who went to preschool, 30 or 55.6%, graduated from high school. Looking at the children who did not go to preschool, what percent graduated from high school? 54' 30.4 % of children who did not go to preschool graduated from high school. (Round to one decimal place as needed.) Step 2: Compare In this sample, the children who attend preschool are more likely to graduate than the children who don't attend preschool. Step 3: Verify…
Five students took a self-confidence test. Their deviation scores were –4, +3, +1, –2, and +2. Assuming that these scores com form a normaldistribution, which deviation represents the highest raw score?
One year Terry had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitcher at his school, with an ERA of 3.02. Also, Karen had the lowest ERA of any female pitcher at the school with an ERA of 3.24. For the males, the mean ERA was 4.364 and the standard deviation was 0.639. For the females, the mean ERA was 3.801 and the standard deviation was 0.959 Find their respective z-scores. Which player had the better year relative to their peers, Terry or Karen? (Note: In general, the lower the ERA, the better the pitcher.) Terry had an ERA with a z-score of Karen had an ERA with a z-score of (Round to two decimal places as needed) Which player had a better year in comparison with their peers? OA. Terry had a better year because of a higher z-score. OB. Karen had a better year because of a lower z-score. OC. Terry had a better year because of a lower z-score. O D. Karen had a better year because of a higher z-score. GIL
For all students who have taken a certain class during the last ten years, theaverage on the mid-term is 83.4 and the standard deviation of the mid-termscores is 7.2; the average on the final is 79.3 and the standard deviation of thescores on the final is 5.1; the correlation between scores on the mid-term andscores on the final is 0.86. 4. My teacher has lost our mid-term scores (but at least has our scores onthe final), so she is fitting a straight line to guess what we probably got onthe mid-term. What’s the equation of the line she is using? 5. I got a 90 on the final. What does my teacher think I got on the midterm?
In a random sample of 38 families, the average weekly food expense was $95.60 with a standard deviation of $22.50. the distribution of weekly food expenses is normally distributed. Find the 99% confidence interval for the average weekly food expense. Round to two decimal places.
Average adult Americans are about one inch taller but nearly a whopping 25 pounds heavier than they were in 1960, according to a report from the Centers for Disease Control and Prevention (CDC). City A is considered one of America's healthiest cities. Is the weight gain since 1960 similar in city A? A sample of n=25 adults suggested a mean increase of 22 pounds with a standard deviation of 9.4 pounds. Is City A significantly different in terms of weight gain since 1960? Complete and interpret 5 step hypothesis testing by hand at a 5% level of significance using a Z-test. Show each step and your work.
Please help me with this question.
A report about how American college students manage their finances includes data from a survey of college students. Each person in a representative sample of 793 college students was asked if they had one or more credit cards and if so, whether they paid their balance in full each month. There were 500 who paid in full each month. For this sample of 500 students, the sample mean credit card balance was reported to be $825. The sample standard deviation of the credit card balances for these 500 students was not reported, but for purposes of this exercise, suppose that it was $205. Is there convincing evidence that college students who pay their credit card balance in full each month have a mean balance that is lower than $907, the value reported for all college students with credit cards? Carry out a hypothesis test using a significance level of 0.01. State the appropriate null and alternative hypotheses. H0: ? = 907 Ha: ? < 907 H0: ? = 907 Ha: ? > 907 H0: ? < 907…
Sam is the manager of a used clothing store. He wants to estimate the average amount a customer spends per visit. A random sample of 70 customers’ receipts gave a mean of = $7.10 with a standard deviation s = $2.30. Find a 99% confidence interval for the average amount spent by all customers. Interpret your findings.
When the correlation between x and y is –1.0, what will the standard deviation of errors be? Why is this?

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