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The line y=x-1 is the tangent line to the a) f(x)= -cosh²x at the point (o, f(o)) the tangent line to the graph of the hunction b) f(x) = In(1+x) at the point (0, f(0)) c) f(x)= (x-1)³ at the point (1,4(1) d) f(x) = tanx-cosh3x at the point (o, f(o)) how I solved it f(0) =-1₁ f(1) =0 after that I don't know how to proceed, should we derive ??

The line y=x-1 is the tangent line to the a) f(x)= -cosh²x at the point (o, f(o)) the tangent line to the graph of the hunction b) f(x) = In(1+x) at the point (0, f(0)) c) f(x)= (x-1)³ at the point (1,4(1) d) f(x) = tanx-cosh3x at the point (o, f(o)) how I solved it f(0) =-1₁ f(1) =0 after that I don't know how to proceed, should we derive ??

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Please show how to do this by deriving
The line y=x-1 a) f(x) = -cosh²m at the point (0, f(o)) b) f(x) = In(1+x) at the point (0, f(o)) c) f(x)= (x-1)³ at the point (1,4(1) d) f(x) = tanx-cosh3x at the point (o, f(o)) is the tangent line to the graph of the hunction how I solved it f(0) = -1, f(1) = 0 after that I don't know how to proceed, should we derive??
Transcribed Image Text:The line y=x-1 a) f(x) = -cosh²m at the point (0, f(o)) b) f(x) = In(1+x) at the point (0, f(o)) c) f(x)= (x-1)³ at the point (1,4(1) d) f(x) = tanx-cosh3x at the point (o, f(o)) is the tangent line to the graph of the hunction how I solved it f(0) = -1, f(1) = 0 after that I don't know how to proceed, should we derive??
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