please answer clearly, so I can understand. Graph is clearly please Graph the following function:Provide your answer below:Drag the movable black point to shift the function, the red points to set the vertical asymptotes, and the blue point at thecorrect set of coordinates. You may click on a point to verify its coordinates. Note that only one period of the function isshown.-2TT -3π/2RESET-TT·••-T4210-4-32-1--2-3--4--5T2·an (7/7 - 3ㅠ8.y = tanTT3TT/2 2T

y = tan (x2 - π8) - 3 Asymptotes of a curve are defined as the lines which approach the curve but never meet the curve. The function tan(x) has its asymptotes at x = (2n+1)π2, where n is an integer. If we are taking only one period then, the function tan(x) has its asymptotes at x = -π2 and x =π2. Therefore, The function y = tan (x2 - π8) - 3 has its asymptotes when tan(x2 - π8) has its asymptotes. If we are taking only one period, then tan(x2 - π8) has its asymptotes as, (x2 - π8) =π2, (x2 - π8) = -π2. Therefore, the required asymptotes' equations are, x = 5π4 and x = -3π4. This is the required graph of the function. Since it is a periodic function, therefore, this is one period of the function from x > -3π4and x <5π4. This is the asymptote x = -3π4, This is the asymptote x =5π4,