The least-square regression line for the given data is y = 0.449x-30.27. Determine the residual of a data point for which x= 90 and y=10, rounding to three decimal places. Temperature, x Number of absences, y OA. -0.14 B. 20.14 C. 115.78 OD. 10.14 72 3 85 7 91 10 90 10 88 8 98 75 100 15 4 15 80 5
The least-square regression line for the given data is y = 0.449x-30.27. Determine the residual of a data point for which x= 90 and y=10, rounding to three decimal places. Temperature, x Number of absences, y OA. -0.14 B. 20.14 C. 115.78 OD. 10.14 72 3 85 7 91 10 90 10 88 8 98 75 100 15 4 15 80 5
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question

Transcribed Image Text:The least-square regression line for the given data is \( \hat{y} = 0.449x - 30.27 \). Determine the residual of a data point for which \( x = 90 \) and \( y = 10 \), rounding to three decimal places.
| Temperature, \( x \) | 72 | 85 | 91 | 90 | 88 | 98 | 75 | 100 | 80 |
|----------------------|----|----|----|----|----|----|----|----|----|
| Number of absences, \( y \) | 3 | 7 | 10 | 10 | 8 | 15 | 4 | 15 | 5 |
Options:
- A. \(-0.14\)
- B. \(20.14\)
- C. \(115.78\)
- D. \(10.14\)
![The least-square regression line for the given data is \(\hat{y} = 2.097x - 0.552\). Determine the residual of a data point for which \(x = 0\) and \(y = -1\), rounding to three decimal places.
Values:
\[
\begin{array}{c|cccccccccc}
x & -5 & -3 & 4 & 1 & -1 & -2 & 0 & 2 & 3 & -4 \\
\hline
y & -10 & -8 & 9 & 1 & -2 & -6 & -1 & 3 & 6 & -8 \\
\end{array}
\]
Options:
- A. \(-0.552\)
- B. \(-0.448\)
- C. \(2.649\)
- D. \(-1.552\)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff46c6c1c-9cf3-4090-96fd-ea5e3513a088%2Fdbf5c8d4-d4e1-4af9-9138-e1cb7689d9e7%2Fo0kbdd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The least-square regression line for the given data is \(\hat{y} = 2.097x - 0.552\). Determine the residual of a data point for which \(x = 0\) and \(y = -1\), rounding to three decimal places.
Values:
\[
\begin{array}{c|cccccccccc}
x & -5 & -3 & 4 & 1 & -1 & -2 & 0 & 2 & 3 & -4 \\
\hline
y & -10 & -8 & 9 & 1 & -2 & -6 & -1 & 3 & 6 & -8 \\
\end{array}
\]
Options:
- A. \(-0.552\)
- B. \(-0.448\)
- C. \(2.649\)
- D. \(-1.552\)
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