The laboratory compaction test of a certain type of soil gives a maximum dry density of 1.486 g/cc' with an optimum moisture content of 12.5%. Determine the field unit weight of the soil in g/cc using the following results of a filed unit weight determination test using sand cone method. Volume of soil excavated from the hole = 0.001337 m Weight of moist soil from the hole = 2220 g Weight of oven dried soil = 1890 g Select one: a. 1.66 b. 1.58 C. 1.92 d. 1.87 It is the ratio of the volume of water to the volume of voids. Select one: a. Degree of saturation

The laboratory compaction test of a certain type of soil gives a maximum dry density of 1.486 g/cc' with an optimum moisture content of 12.5%. Determine the field unit weight of the soil in g/cc using the following results of a filed unit weight determination test using sand cone method. Volume of soil excavated from the hole = 0.001337 m Weight of moist soil from the hole = 2220 g Weight of oven dried soil = 1890 g Select one: a. 1.66 b. 1.58 C. 1.92 d. 1.87 It is the ratio of the volume of water to the volume of voids. Select one: a. Degree of saturation

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The following are results of a field unit weight determination test using sand cone method: Volume of hole = 0.0019 m3 Mass of moist soil from hole = 3.48 kg Water content = 12.43% Max. dry unit weight from a laboratory compaction test = 19.56 kN/m3 Determine the relative compaction, in percent. Hint: Relative compaction = Field dry unit weight / Max dry unit weight (lab)
A field sand cone test is performed on a layer of compacted fill. determined that the fill soil has a maximum dry unit weight of approximately 120 pcf. Determine the relative compaction of the compacted fill. Unit weight of dry uniform of sand: 95 pcf Weight of sand to fill the cone: 1.10 lb weight of jar + cone + sand (before test): 16.5 lb Weight of jar + cone + sand (after test): 10.5 lb Weight of moist soil excavated from hole: 6.60 lb Moisture content of soil from hole: 10 %
A sample of soil compacted according to a standard Proctor test has a unit weight of 130.9 lb/ft^3 at 100% compaction and at optimum water content of 14%. What is the dry unit weight? If the voids become filled with water what would be the saturated unit weight? Assume Gs= 2.67.
9. The field unit weight of the soil sample is 1960 kg/m³, and the unit weight of the soil particle is 2700 kg/m³. If emax=0.69 and emin = 0.44. a) Compute the dry unit weight if the water content is 11% b) Compute the void ratio of the soil sample. c) Compute the relative density of the soil sample.
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The unit weight of a compacted sand backfill was determined by field measurement to be 1738 kg/m3. The water content and void ratio of the laboratory compacted soil was 10.2% and 60.7% respectively. What was the degree of compaction achieved in field? Assume water content remain constant (G = 2.7). %3!
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Q # 1. Organic soils are typically characterized by high void ratio, low specific gravity, and high compressibility. Following are the results of a consolidation test on a sample of organic soil. Pressure, o (kN/m2) Change in dial reading, AH (mm) 0.284 12 0.150 24 0.315 48 0.564 100 0.823 200 2.25 400 5.34 Given that the initial height of the specimen = 20.6 mm, mass of dry specimen = 12 g, area of specimen = 31.67 cm2 and G, = 2.49. Plot the e, log o' curve. b. Determine the preconsolidation pressure. a.