The following are results of a field unit weight determination test using sand cone method: Volume of hole = 0.0019 m3 Mass of moist soil from hole = 3.48 kg Water content = 12.43% Max. dry unit weight from a laboratory compaction test = 19.56 kN/m3 Determine the relative compaction, in percent. Hint: Relative compaction = Field dry unit weight / Max dry unit weight (lab)

The following are results of a field unit weight determination test using sand cone method: Volume of hole = 0.0019 m3 Mass of moist soil from hole = 3.48 kg Water content = 12.43% Max. dry unit weight from a laboratory compaction test = 19.56 kN/m3 Determine the relative compaction, in percent. Hint: Relative compaction = Field dry unit weight / Max dry unit weight (lab)

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter6: Soil Compaction

Section: Chapter Questions

Problem 6.7P

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1. Sand cone equipment is used to determine an in-place unit weight (field density test) on a compacted earth fill. Ottowa sand is used in the cone and is known to have a bulk density of 100 pcf. a. From the information given below, determine the in-place dry unit weight of the tested soil, and the water content. Soil sample dug from test hole wet weight = 4.62 lb Dried Weight of soil sample = 4.02 lb Weight of Ottowa Sand (Sand Cone) to fill test hole = 3.60 lb b. Determine the percentage of compaction of the tested soil if the laboratory moisture unit weight curve indicates a dry unit weight of 115 pcf and optimum moisture content of 13 percent.
An in-place density determination (in-place unit weight) is made for the sand in a borrow pit using a balloon-type density apparatus. The damp sample dug from a test hole is found to weigh 37.90 N. The volume of the test hole is 0.00184m2. A. Compute the wet unit weight. B. This soil is to have a water content of 15%. Compute the dry unit weight of the soil. C. Compute the specific gravity of the soil if it has a void ratio of 0.423
The following results were obtained from a standard compaction test on a soil: 2010 2092 2114 | 2100 2055 Mass (g) Water content (%) | 12.8 | 14.5 15.6 | 16.8 | 19.2 The value of G, is 2.67. The volume of the mould is 1000 cm³. 1) Plot the curve of compaction and give the optimum water content and maximum dry density. 2) Plot also the curves of saturation for S=100%, S=95% and S=90%.
A modified Proctor compaction test was carried out using a cylindrical moldwith a 1000 ml volume. Table 2 summarizes the results. a. Plot the compaction and ZAV curves (RD=2.75 and ρwater=1000 kg/m3)b. Determine the maximum dry density and the optimum moisture content Table 2 Moisture Content (%)Mass of WetSample (g)10.5 2033.211.8 2146.613.0 2203.514.9 2183.116.4 2147.617.6 2116.8
A field sand cone test is performed on a layer of compacted fill. determined that the fill soil has a maximum dry unit weight of approximately 120 pcf. Determine the relative compaction of the compacted fill. Unit weight of dry uniform of sand: 95 pcf Weight of sand to fill the cone: 1.10 lb weight of jar + cone + sand (before test): 16.5 lb Weight of jar + cone + sand (after test): 10.5 lb Weight of moist soil excavated from hole: 6.60 lb Moisture content of soil from hole: 10 %
A modified Proctor compaction test was carried out using a cylindrical moldwith a 1000 ml volume. Table 2 summarizes the results.a. Plot the compaction and ZAV curves (RD=2.75 and ρwater=1000 kg/m3).b. Determine the maximum dry density and the optimum moisture content.
Answer a and b
The results of a standard Proctor test are given in the following table. Determine the maximum dry unit weight of compaction and the optimum moisture content. Also determine the moisture content required to achieve 95% of γd(max). Calculate and plot the 80% and 100% saturation lines.
Laboratory compaction test results on a clayey soil are listed in the table below. Moisture content (%) Dry unit weight (kN/m³) 6 14.80 8 17.45 9 18.52 11 18.9 12 18.5 14 16.9 The following are the results of a field unit weight determination test on the same soil with the sand cone method: Calibrated dry density of Ottawa sand = 1,560 kg/m³ Calibrated mass of Ottawa sand to fill the cone = 0.565 kg Mass of jar + cone + sand (before use) = 7.59 kg Mass of jar + cone + sand (after use) = 4.78 kg Mass of moist soil from hole = 2.85 kg Moisture content of moist soil = 15.2% Determine: a. Dry unit weight of compaction in the field. (Enter your answer to three significant figures.) Ya = ]kN/m³ b. Relative compaction in the field. (Enter your answer to two significant figures.) R = |%
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The laboratory compaction test of a certain type of soil gives a maximum dry density of 1486 g/m3 with an optimum moisture content of 12.5%. The following are the results of a field unit weight determination test using sand cone method. Volume of soil excavated from the hole = 0.001337 m3 Weight of soil from the hole when wet = 2220 g Weight of soil from the hole when dried = 1890 g Determine the field unit weight of soil in g/cm3. Determine the relative compaction, then tell whether it is within the allowable range for relative compaction of 95 ± 0.20?