The joint probability function for the randomvariables X and Y, P(X,Y), is given in matrixbelow. Then, the mean value of X and Y areP(X, Y)O2.15, 2.452.1, 2.12.1, 2.452.1, 2.52.2, 2.44=11 [0.05x 20.053L 0y20.050.10.230.10.350.1

Answered: Image /qna-images/answer/27042df6-59b3-4f7a-9137-7d56baa285f2.jpg

Answered: The joint probability function for the…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

See similar textbooks

Similar questions

Recall that two events A and B are called independent if p(AB) = p(A)p(B). Similarly two random variables x and y are called independent if the joint probability function f(x, y) = g(x)h(y). Show that if x and y are independent, then the expectation or average of xy is E(xy) = E(x)E(y) = µxµy.
The joint probability function for the random variables X and Y, P(X,Y), is given in matrix below. Then, the mean value of X and Y are P(X, Y) = 1 1 [0.05 0.05 x 2 30 y 2 0.05 0.1 0.2 3 0.1 0.35 0.1 2.2, 2.44 2.1, 2.1 2.1, 2.45 2.15, 2.45 2.1, 2.5 O
A random variable X has the following probability mass function for x = 0, 1, 2, 5. Based (PMF): P(X= x) = (x+1) 12 on this PMF, what is P(X≥ 2)? 5/12 1/2 3/4 11/12
Determine E(x) and E(y)
The random variable X takes values -1, 0, 1 with probabilities 1/8, 3/8, 4/8 respectively. a) Write the CDF of X. b) Write the PMF of Y = X² + 2. %3D c) Compute E(Y).
A- Let x be a discrete random variable with probability distribution function f(x)=k( x2 +20) and x= −1,1,2,3. Find the value of k. Find the Variance of X. B- Let x denote a discrete random variable which can take the values −2,0, and 5. Given that the expectation of X is 8/100 and P(X=−2)=8/20 , find P(X=5).
he joint pat of the random variable X and Yis iven in the below matrix. Find the mean value f X and Y: P(X,Y)= X 2.45 and 2.1 1.9 and 2.45 O 1.9 and 2.1 2.1 and 2.45 Y 0.05 0.05 0.1 0.05 0.1 0.35 0 0.2 0.1
The possible values of a discrete random variable X are 0, 1, 3, and 6 with respective probabilities 0.2, 0.3, 0.1, 0.4. Find E[X] and Var(X).
A random variable takes the values 1, 2, 3 where P(x-1)%3D0.5 and E(x)=1.7, then P(x >2]X>1)=D O a. 0.2 O b. 0.8 O .1 O d. 0.4
Given that f(x, y) = (2x+2y)/2k if x = 0,1 and y = 1,4, is a joint probability distribution function for the random variables X and Y. Find: The value of K
X has been defined as the Poisson random variable. Thus, P (X = 1) = 0.149 and P (X = 2) = 0.224 are given. Find out what the probability P (X = 0) is.

Recommended textbooks for you

Advanced Engineering Mathematics

Advanced Math

ISBN:

9780470458365

Author:

Erwin Kreyszig

Publisher:

Wiley, John & Sons, Incorporated

Numerical Methods for Engineers

Advanced Math

ISBN:

9780073397924

Author:

Steven C. Chapra Dr., Raymond P. Canale

Publisher:

McGraw-Hill Education

Introductory Mathematics for Engineering Applicat…

Advanced Math

ISBN:

9781118141809

Author:

Nathan Klingbeil

Publisher:

WILEY

Advanced Engineering Mathematics

Advanced Math

ISBN:

9780470458365

Author:

Erwin Kreyszig

Publisher:

Wiley, John & Sons, Incorporated

Numerical Methods for Engineers

Advanced Math

ISBN:

9780073397924

Author:

Steven C. Chapra Dr., Raymond P. Canale

Publisher:

McGraw-Hill Education

Introductory Mathematics for Engineering Applicat…

Advanced Math

ISBN:

9781118141809

Author:

Nathan Klingbeil

Publisher:

WILEY

Mathematics For Machine Technology

Advanced Math

ISBN:

9781337798310

Author:

Peterson, John.

Publisher:

Cengage Learning,

Basic Technical Mathematics

Advanced Math

ISBN:

9780134437705

Author:

Washington

Publisher:

PEARSON

Topology

Advanced Math

ISBN:

9780134689517

Author:

Munkres, James R.

Publisher:

Pearson,

SEE MORE TEXTBOOKS

The joint probability function for the random variables X and Y, P(X,Y), is given in matrix below. Then, the mean value of X and Y are P(X,Y)= 2.15, 2.45 O2.1, 2.1 O2.1, 2.45 O2.1, 2.5 2.2, 2.44 1 10.05 0.05 x 2 3 0 y 2 0.05 0.1 0.2 3 0.1 0.35 0.1.