The joint pmf of the random variables X, Y and Z is given in the table. Y Z=1 X 1 2 3 1 .001 .002 .003 2 .006 .005 .004 3 .007 .008 .009 a) Determine fx, (2, 2) b) Determine fx,y)-1(2, 2) Y 1 2 3 Z=2 1 .07 .08 .09 X N 2 .06 .05 .04 3 .01 .02 .03 Y 1 2 3 Z = 3 1 .03 .02 .07 X 2 .01 .145 3 .05 .04 .06 .08

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