Y = 0 Y = 1 Y = 2 Px(x) X = 4 1/5 1/12 1/3 X = 5 1/10 2/5 X = 6 Py(y) 3/5 3/20 1
A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Provided that X and Y are independent and discreet random variables. Fill in the table below with missing values. Show calculations.

Transcribed Image Text:This table represents a joint probability distribution of two discrete random variables, X and Y. The entries in the table correspond to the joint probabilities \( P(X = x, Y = y) \).
### Table Explanation:
- **Rows and Columns**
- The rows represent different values of \( Y \): \( Y = 0, 1, \) and \( 2 \).
- The columns represent different values of \( X \): \( X = 4, 5, \) and \( 6 \).
- **Joint Probabilities**
- The intersection of each row and column gives the probability \( P(X = x, Y = y) \).
- For example, \( P(X = 4, Y = 0) = \frac{1}{5} \).
- **Marginal Probabilities**
- The last column labeled \( P_Y(y) \) provides the marginal probabilities of \( Y \).
- \( P_Y(Y = 0) = \frac{3}{5} \)
- \( P_Y(Y = 1) = \) (value not given)
- \( P_Y(Y = 2) = \frac{3}{20} \)
- The last row labeled \( P_X(x) \) provides the marginal probabilities of \( X \).
- \( P_X(X = 4) = \frac{1}{3} \)
- \( P_X(X = 5) = \frac{2}{5} \)
- \( P_X(X = 6) = \) (value not given but can be computed)
- **Total Probability**
- The sum of the marginal probabilities \( P_Y(y) \) and \( P_X(x) \) across their respective rows and columns should equal 1, indicating a complete probability distribution.
This table is used to understand the relationship and individual distributions of the random variables \( X \) and \( Y \).
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