A random variable X has the following probability mass function (+1) for x = 0, 1, 2, 5. Based 12 on this PMF, what is P(X ≥ 2)? (PMF): P(X= x) = = 5/12 1/2 3/4 11/12

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 21E
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A random variable X has the following probability mass function
for x = 0, 1, 2, 5. Based
(PMF): P(X= x) = (x+1)
12
on this PMF, what is P(X≥ 2)?
5/12
1/2
3/4
11/12
Transcribed Image Text:A random variable X has the following probability mass function for x = 0, 1, 2, 5. Based (PMF): P(X= x) = (x+1) 12 on this PMF, what is P(X≥ 2)? 5/12 1/2 3/4 11/12
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