For a random variable X, suppose that E[X] = 1 and Var(X) = 5. Then %3D (a) E[(2+ X)²] = (b) Var(2 + 3X) = Netsu ortiol ordit on this problem

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Q: 1 The discrete random variable X has Var (X) = 5 Find Var (4X – 3)

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A: Given, E(X+1)=3 Then E(X)+1=3          E(X) =2 and E(X2+X)=9       E(X2)+E(X)=9       E(X2)+2=9…

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A:

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A:

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Q: = 1- Q(x).

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A: