The iodination of salicylamide was carried out analogous to Experiment 12 in your “Green Organic Chemistry" textbook: Nal NaOCI lodosalicylamide EIOH OH Salicylamide The 'H NMR spectra of the starting material and product are posted on Blackboard. Processed data are posted in the document A2-spectra.pdf. If you would rather process the data yourself, the raw FID's are also posted on Blackboard with the filenames shown below. In cach case the solvent is de-DMSO (if you process the data yourself, be sure to reference the center peak of DMSO to 2.5 ppm). Salicylamide (the starting material): The recrystallized iodosalicylamide (product) salicylamide.mrc iodo salicylamide xtal.mrc 8. In both the starting material and product the chemical shift of the hydroxyl proton is approximately 13 ppm. Table 21.2 in your "Techniques in Organic Chemistry" textbook gives 4.0 – 8.0 ppm as the typical range for phenolic protons. Explain this apparent discrepancy.
The iodination of salicylamide was carried out analogous to Experiment 12 in your “Green Organic Chemistry" textbook: Nal NaOCI lodosalicylamide EIOH OH Salicylamide The 'H NMR spectra of the starting material and product are posted on Blackboard. Processed data are posted in the document A2-spectra.pdf. If you would rather process the data yourself, the raw FID's are also posted on Blackboard with the filenames shown below. In cach case the solvent is de-DMSO (if you process the data yourself, be sure to reference the center peak of DMSO to 2.5 ppm). Salicylamide (the starting material): The recrystallized iodosalicylamide (product) salicylamide.mrc iodo salicylamide xtal.mrc 8. In both the starting material and product the chemical shift of the hydroxyl proton is approximately 13 ppm. Table 21.2 in your "Techniques in Organic Chemistry" textbook gives 4.0 – 8.0 ppm as the typical range for phenolic protons. Explain this apparent discrepancy.
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ISBN:9781305957404
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:The iodination of salicylamide was carried out analogous to Experiment 12 in your "Green Organie
Chemistry" textbook:
Nal
NaOCI
`NH
lodosalicylamide
EIOH
OH
Salicylamide
The 'H NMR spectra of the starting material and product are posted on Blackboard. Processed data are
posted in the document A2-spectra.pdf. If you would rather process the data yourself, the raw FID's are
also posted on Blackboard with the filenames shown below. In cach case the solvent is de-DMSO (if you
process the data yourself, be sure to reference the center peak of DMSO to 2.5 ppm).
Salicylamide (the starting material):
The recrystallized iodosalicylamide (product)
salicylamide.mrc
iodo salicylamide xtal.mrc
8. In both the starting material and product the chemical shift of the hydroxyl proton is approximately
13 ppm. Table 21.2 in your “Techniques in Organic Chemistry" textbook gives 4.0 - 8.0 ppm as the
typical range for phenolic protons. Explain this apparent discrepancy.
Expert Solution

Step 1
Increase in chemical shifts suggest that the proton is deshielded. Hydrogen bond interaction is one of the factor that makes a proton deshielded.
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