The integrals arise when finding the Fourier series expansion of eax over the interval -L< x < L. Use the result cos nл = (-1)" for integral values of n to establish the stated result. Le -π eax sin nxdx = (-1)+1n(еax - e-ar (a²+n²) for integral values of n.
The integrals arise when finding the Fourier series expansion of eax over the interval -L< x < L. Use the result cos nл = (-1)" for integral values of n to establish the stated result. Le -π eax sin nxdx = (-1)+1n(еax - e-ar (a²+n²) for integral values of n.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:The integrals
arise when finding the
Fourier series expansion of eax over the interval -L< x <
L. Use the result cos nл = (-1)" for integral values of n to
establish the stated result.
Le
-π
eax sin nxdx =
(-1)+1n(еax
- e-ar
(a²+n²)
for integral
values of n.
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