The hypotheses are: Ο Ho: μ18; Ha:μ4 18 О Но:р > 18; На:р < 18 О Но:р 3 18;B На:р 2 18 О Но:р < 18;B На:р > 18 Ο Ho: μ 2 18; Ha : μ < 18 О Но:и < 18;B На:и > 18

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A Grades for Ivan Zepeda: 40231 X
A HW 9.5
e.instructure.com/courses/2177802/assignments/13744607
A Maps
Test the claim that a population mean is more than 18. A random sample of 20 values yields = 18.07
and s = 1.6. Use a = 0.10.
1. The population distribution requirement for this test is:
O Need a normally distributed population since n < 30
O None sincen > 30
O None since this is a Z-test
O Need a normally distributed population since this is a T-test
ne
The hypotheses are:
O Ho:µ = 18; Ha:p 18
О Но:р > 18;B На:р < 18
О Но:р — 18;B На:р 2 18
О Но:р < 18;B На:р > 18
О Но: 2 18;B На:в < 18
Ο Ho: μ< 18; Ha: μ > 18
ctor
2. This is a O rightO twoO left tailed test and the distribution used is
OT since o not known
OZ since o known
OZ since testing a proportion
The Degrees of Freedom are
O 19
O 20
ON/A; this is a Z-test
3. The STS (round to 3 decimals) is:
Transcribed Image Text:A Grades for Ivan Zepeda: 40231 X A HW 9.5 e.instructure.com/courses/2177802/assignments/13744607 A Maps Test the claim that a population mean is more than 18. A random sample of 20 values yields = 18.07 and s = 1.6. Use a = 0.10. 1. The population distribution requirement for this test is: O Need a normally distributed population since n < 30 O None sincen > 30 O None since this is a Z-test O Need a normally distributed population since this is a T-test ne The hypotheses are: O Ho:µ = 18; Ha:p 18 О Но:р > 18;B На:р < 18 О Но:р — 18;B На:р 2 18 О Но:р < 18;B На:р > 18 О Но: 2 18;B На:в < 18 Ο Ho: μ< 18; Ha: μ > 18 ctor 2. This is a O rightO twoO left tailed test and the distribution used is OT since o not known OZ since o known OZ since testing a proportion The Degrees of Freedom are O 19 O 20 ON/A; this is a Z-test 3. The STS (round to 3 decimals) is:
=ge.instructure.com/courses/2177802/assignments/13744607
e Maps
2. This is a O rightO twoO left tailed test and the distribution used is
OT since o not known
OZ since o known
OZ since testing a proportion
The Degrees of Freedom are
O 19
O 20
ON/A; this is a Z-test
3. The STS (round to 3 decimals) is:
The P-value (round to 4 decimals) is:
4. The decision at a = 0.10 is:
O Do not reject Ho since P < a
O Do not reject Ho since P > a
O Reject Ho since P > a
O Reject Ho since P < a
The conclusion is:
O There is sufficient evidence to reject the claim that the popuation mean is more than 18
O There is sufficient evidence to support the claim that the population mean is more than 18
O There is insufficient evidence to support the claim that the population mean is more than 18
O There is insufficient evidence to reject the claim that the population mean is more than 18
Submit Question
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7
Transcribed Image Text:=ge.instructure.com/courses/2177802/assignments/13744607 e Maps 2. This is a O rightO twoO left tailed test and the distribution used is OT since o not known OZ since o known OZ since testing a proportion The Degrees of Freedom are O 19 O 20 ON/A; this is a Z-test 3. The STS (round to 3 decimals) is: The P-value (round to 4 decimals) is: 4. The decision at a = 0.10 is: O Do not reject Ho since P < a O Do not reject Ho since P > a O Reject Ho since P > a O Reject Ho since P < a The conclusion is: O There is sufficient evidence to reject the claim that the popuation mean is more than 18 O There is sufficient evidence to support the claim that the population mean is more than 18 O There is insufficient evidence to support the claim that the population mean is more than 18 O There is insufficient evidence to reject the claim that the population mean is more than 18 Submit Question G Search or type URL & %23 7
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