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? X= -8+ √224 X = -8± √ 224 X-8+2 How did the answer become : 8+ √254 a 3.5 Taada -11.5

? X= -8+ √224 X = -8± √ 224 X-8+2 How did the answer become : 8+ √254 a 3.5 Taada -11.5

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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How did the answer become 3.5? And -11.5
2 X = X -8± √/224 2 -8√ 224 224 How did the omswer becomme " Problem >-8422 X = = 8+ √254 3.5 2 Toada -11.5 2 A=1W 40= X(X + 8
Transcribed Image Text:2 X = X -8± √/224 2 -8√ 224 224 How did the omswer becomme " Problem >-8422 X = = 8+ √254 3.5 2 Toada -11.5 2 A=1W 40= X(X + 8
Hcc MyEagle 2 awu.connectmath.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IQ1HXBxM9hozYUZCiw4JIKPXwidPMfFrdfs... x HCC Connect Math connect™ MATH Answers Question of A1 of View question in a popup an Und Part 1 of 2 Part 2 of 2 Ca Question A rectangular garden covers 40 yd. The length is 8 yd longer than the width. Find the length and width Round your answers to the nearest tenth of a yard. Explanation Let I represent the width of the rectangle Then, I+S represents the length of the rectangle The area is given by the product of the length and the width A=Iw 40 = x(x+8) Apply the distributive property ²+x=40 Set one side equal to zero. ²+8x-40=0 Apply the quadratic formula with a=1, b-3, and c-40. x = -√/8²-40c 2a O Search By Ar L 6232-MATH-1314-College Algebra-RT-11667 The length is approximately 11.5 yd Section 15 Homework I = -32/224 x = -82/224 X=-3+√/224 235 x=-3-√2342-15 Reject -11.5 because the measure of a side must be positive. The width of the rectangle is given by x 3.5 yd The length of the rectangle is given by x+8 (3.5 yd+8-11.5 yd The width is approximately 3.5 yd and the length is approximately 11.5 yd < The width is approximately 3.5 yd x=(8) ± √(8)³-4(1)(-40) 2(1) ... 12345 hp 789 > H X Save For Lar M Walcom, Noor Dalgal ockHelp O 1.5 Son Exc13.14 SubArt McGraw-Hill Connect Math W F
Transcribed Image Text:Hcc MyEagle 2 awu.connectmath.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IQ1HXBxM9hozYUZCiw4JIKPXwidPMfFrdfs... x HCC Connect Math connect™ MATH Answers Question of A1 of View question in a popup an Und Part 1 of 2 Part 2 of 2 Ca Question A rectangular garden covers 40 yd. The length is 8 yd longer than the width. Find the length and width Round your answers to the nearest tenth of a yard. Explanation Let I represent the width of the rectangle Then, I+S represents the length of the rectangle The area is given by the product of the length and the width A=Iw 40 = x(x+8) Apply the distributive property ²+x=40 Set one side equal to zero. ²+8x-40=0 Apply the quadratic formula with a=1, b-3, and c-40. x = -√/8²-40c 2a O Search By Ar L 6232-MATH-1314-College Algebra-RT-11667 The length is approximately 11.5 yd Section 15 Homework I = -32/224 x = -82/224 X=-3+√/224 235 x=-3-√2342-15 Reject -11.5 because the measure of a side must be positive. The width of the rectangle is given by x 3.5 yd The length of the rectangle is given by x+8 (3.5 yd+8-11.5 yd The width is approximately 3.5 yd and the length is approximately 11.5 yd < The width is approximately 3.5 yd x=(8) ± √(8)³-4(1)(-40) 2(1) ... 12345 hp 789 > H X Save For Lar M Walcom, Noor Dalgal ockHelp O 1.5 Son Exc13.14 SubArt McGraw-Hill Connect Math W F
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