Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
100%
How did the answer become
3.5?
And -11.5
![2
X =
X
-8± √/224
2
-8√ 224
224
How did the omswer becomme "
Problem
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X = = 8+ √254 3.5
2
Toada -11.5
2
A=1W
40= X(X + 8](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff8411dad-f4bd-4852-a80d-7160671c8489%2F07691280-fc04-457c-bd69-1665e9e70500%2F6t3l7c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2
X =
X
-8± √/224
2
-8√ 224
224
How did the omswer becomme "
Problem
>-8422
X = = 8+ √254 3.5
2
Toada -11.5
2
A=1W
40= X(X + 8
![Hcc MyEagle
2
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Answers
Question of A1 of View question in a popup
an Und
Part 1 of 2
Part 2 of 2
Ca
Question
A rectangular garden covers 40 yd. The length is 8 yd longer than the width. Find the length and width
Round your answers to the nearest tenth of a yard.
Explanation
Let I represent the width of the rectangle
Then, I+S represents the length of the rectangle
The area is given by the product of the length and the width
A=Iw
40 = x(x+8)
Apply the distributive property
²+x=40
Set one side equal to zero.
²+8x-40=0
Apply the quadratic formula with a=1, b-3, and c-40.
x = -√/8²-40c
2a
O Search
By Ar
L
6232-MATH-1314-College Algebra-RT-11667
The length is approximately 11.5 yd
Section 15 Homework
I =
-32/224
x = -82/224
X=-3+√/224 235
x=-3-√2342-15
Reject -11.5 because the measure of a side must be positive.
The width of the rectangle is given by x 3.5 yd
The length of the rectangle is given by x+8 (3.5 yd+8-11.5 yd
The width is approximately 3.5 yd and the length is approximately 11.5 yd
<
The width is approximately 3.5 yd
x=(8) ± √(8)³-4(1)(-40)
2(1)
...
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Save For Lar
M
Walcom, Noor Dalgal
ockHelp O
1.5 Son Exc13.14
SubArt
McGraw-Hill Connect Math
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F](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff8411dad-f4bd-4852-a80d-7160671c8489%2F07691280-fc04-457c-bd69-1665e9e70500%2F8nj9h4aj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Hcc MyEagle
2
awu.connectmath.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IQ1HXBxM9hozYUZCiw4JIKPXwidPMfFrdfs...
x HCC Connect Math
connect™
MATH
Answers
Question of A1 of View question in a popup
an Und
Part 1 of 2
Part 2 of 2
Ca
Question
A rectangular garden covers 40 yd. The length is 8 yd longer than the width. Find the length and width
Round your answers to the nearest tenth of a yard.
Explanation
Let I represent the width of the rectangle
Then, I+S represents the length of the rectangle
The area is given by the product of the length and the width
A=Iw
40 = x(x+8)
Apply the distributive property
²+x=40
Set one side equal to zero.
²+8x-40=0
Apply the quadratic formula with a=1, b-3, and c-40.
x = -√/8²-40c
2a
O Search
By Ar
L
6232-MATH-1314-College Algebra-RT-11667
The length is approximately 11.5 yd
Section 15 Homework
I =
-32/224
x = -82/224
X=-3+√/224 235
x=-3-√2342-15
Reject -11.5 because the measure of a side must be positive.
The width of the rectangle is given by x 3.5 yd
The length of the rectangle is given by x+8 (3.5 yd+8-11.5 yd
The width is approximately 3.5 yd and the length is approximately 11.5 yd
<
The width is approximately 3.5 yd
x=(8) ± √(8)³-4(1)(-40)
2(1)
...
12345
hp
789 >
H
X
Save For Lar
M
Walcom, Noor Dalgal
ockHelp O
1.5 Son Exc13.14
SubArt
McGraw-Hill Connect Math
W
F
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