The hydrogen atom radial Hamiltonian 1 ə Ә 2r² ar -2 Ĥ = = can be written in atomic units as l(l + 1) 1 1 a 2r² r 2r² ər 1 √2π + with its lowest eigenvalue, E100 100 (r, 0.4) er. In the last equality for F, we have substituted f = 0 (s-orbital). (a) Use a Gaussian function, (r) = e-ar²/2, to represent this lowest eigenstate and find an expression for the lowest energy level as a function of the parameter, a. Note that Sºx xe-Br2 50⁰: xe-Bx2, ²017) - 1²/3 ar 1 == -, corresponding to the normalized eigenfunction, dx = 2/13 √ x²e-³x² dx = 2ß 4 -2 TT B3 dx = 3 TL 8 B5
The hydrogen atom radial Hamiltonian 1 ə Ә 2r² ar -2 Ĥ = = can be written in atomic units as l(l + 1) 1 1 a 2r² r 2r² ər 1 √2π + with its lowest eigenvalue, E100 100 (r, 0.4) er. In the last equality for F, we have substituted f = 0 (s-orbital). (a) Use a Gaussian function, (r) = e-ar²/2, to represent this lowest eigenstate and find an expression for the lowest energy level as a function of the parameter, a. Note that Sºx xe-Br2 50⁰: xe-Bx2, ²017) - 1²/3 ar 1 == -, corresponding to the normalized eigenfunction, dx = 2/13 √ x²e-³x² dx = 2ß 4 -2 TT B3 dx = 3 TL 8 B5
Related questions
Question
100%

Transcribed Image Text:The hydrogen atom radial Hamiltonian can be written in atomic units as
1_ª (r² - )
2r²
Ĥ
=
1
√2π
dx =
1
2ß
1 a
2r² ər
1
-, corresponding to the normalized eigenfunction,
with its lowest eigenvalue, E100
100 (r, 0.4) =
er. In the last equality for F, we have substituted f = 0 (s-orbital).
(a) Use a Gaussian function, (r) = e-ar²/2, to represent this lowest eigenstate and find
an expression for the lowest energy level as a function of the parameter, a. Note that
Sººx
xe-Br2
50⁰0 3 x¹e-³x² dx
3 T
8
l(l + 1) 1
2r²
r
+
==
√° x²e-³x² dx =
4
2
²017) - 1²/3
ar
TL
B3
=
B5
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 3 images

Follow-up Questions
Read through expert solutions to related follow-up questions below.
Follow-up Question

Transcribed Image Text:(b) What is the variational energy for the optimized trial function? Compare this energy to
the exact value (-2), and evaluate the percent error of your value:
Evar - Eexact
Eexact
x 100%
Solution