1. Returning to our old favorite, an infinite square potential is defined by I<0: U (x) = ∞ 0 < x < L: U (x) = 0 r > L: U (x) = ∞ As we've shown, the normalized eigenstates for this systems are /2 tin (7) = Vžsin (Fnz) Show explicitly that the states are orthogonal; that is | (x) vn (x) dx = ôn,m (Hint: You already know this is equal to 1 when n = m. For the case where n m, use standard trig identities to turn the product of sines into cosines of the sum and difference of the arguments.)

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1. Returning to our old favorite, an infinite square potential is defined by
I<0: U (x) = ∞
0 < x < L: U (x) = 0
r > L: U (x) = ∞
As we've shown, the normalized eigenstates for this systems are
/2
tin (7) = Vžsin (Fnz)
Show explicitly that the states are orthogonal; that is
| (x) vn (x) dx = ôn,m
(Hint: You already know this is equal to 1 when n = m. For the case where n m, use
standard trig identities to turn the product of sines into cosines of the sum and difference of
the arguments.)
Transcribed Image Text:1. Returning to our old favorite, an infinite square potential is defined by I<0: U (x) = ∞ 0 < x < L: U (x) = 0 r > L: U (x) = ∞ As we've shown, the normalized eigenstates for this systems are /2 tin (7) = Vžsin (Fnz) Show explicitly that the states are orthogonal; that is | (x) vn (x) dx = ôn,m (Hint: You already know this is equal to 1 when n = m. For the case where n m, use standard trig identities to turn the product of sines into cosines of the sum and difference of the arguments.)
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