The horizontal Y fitting, splits Qu into fwo equal flow rates. At seetion 1 Q=4 & Pi=20pst gage. Ignore any lusses, compute 3fessures Pz& Pz e A2こ4m 30 waters di=6in る。 d3z 3nches

Q: Apipe through which water flowing is having Dia meter 30cm and 15 cm at Cross section 1, 2…

A: d1=30cm d2=15cm V1=4.5m/s

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Q: Frad Total ActfrueThrust and pointaf applicatia

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Q: HW #3 Sbom e:0,3mm レ=300m Find D usiug covel Brook Dンて without e9nivalent Lenght Slom

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Q: DETERMNE ALL BAR FORCES. N ORDE AS LUTED DELOW. AB AC BC EG BD F6 8 YOUR YO HAS WAJA YATIAS BE CVBV…

A: Converting the udl into Nodal forces, and redrawing the trussLength of member CE =EG = 4.12 kN

Q: VII. Data Collection and Analysis Staff Reading (m) Rise Fall RL Remarks Station BS IS FS (m) (m)…

A: To complete the table by rise and fall method

Q: Example 7): For the concrete dam shown find the uplift pressure at base of the dam. 1.00m 5.00m…

A: U1 44.44 U2 41.79 U3 39.24 U4 36.62 U5 46.4 U6 43.16 U7 39.8 U8 36.6 U9 33.3 U10…

Q: water flows from a reservoir (A) showe in throgh a pipe of diameter (di=120mm) and lengh (Lis 20 m /…

A:

Q: 3 4.20 B A 4.0 m BAR WEIGHING 100 N IS REUTING ON A SMOOTH FLOOR AND AGAINST A MOOTH WALL AT POINTr…

A: To find the value of P

Q: Y Usingdata in Figuré below, Eind the Flow direetion and the hydraulic graliont well, h=18-72m 100…

A: Solution Given data Well name Elevation well 1 18.72 m well 2 18.10 m well 3 18.45 m

Q: Answer only that SECOND question thanks. Water is issued verAticalFly at the rate of 35462 L/Ts…

A: The objective of the question is to calculate the power delivered by the water jet to the turbine.…

Q: 2/ 3 m WIL 1 Water Given:- Siphon of 5 cm diameter. Cm hf₁-2 1.5 (m) hf 2-3 Required:- Values of I…

A: d = 0.05 m hf1-2 = 1.5 m hf2-3 = 2.5 m

Q: ACTIVITY NO. 7 : PROBLEM 1: GIVEN: COLUMNS fc' = 28 MPa fy REQUIRED: мра WITH Øjen if ė = 250 mm…

A: fc = 28 MPafy = 420 MPae = 250 mmh = 500 mmcover = 75 mmRebars 4-28 mmb = 400 mm

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Q: resultant couple moment. 10 kN 4 3. 4 m- 1 m B 1 m 3 45 10 kN

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A: given data:

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A: This question is related to the Structure Analysis. In this question Reaction at B (Rb or By ) will…

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A: Q = 8000 cfs = 8000 * 0.30483 = 226.535 m3 /s

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Q: Answer only that SECOND question thanks. Water is issued verAticalFly at the rate of 35462 L/Ts…

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Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.