Example 4 A decision has to be made on whether touse 3 in. or 4 in. ID tubing for a well with the following conditions: Steady state inflow Solution; Initial pressure PI Bubble point pressure Depth (TVD) Required THP GOR 2,500 psi 2.0 STB/psi 1,200 psi 5,000 ft 300 psi 200 SCF/bbl (i) Calculate the flow capacity of the well for 4 in. and 3 in. ID use the attached gradient curves (ii) Comment on the general sizing of the available tubing strings. 1. Plot the IPR BHP: = 2500 psi IPR must pass through: Q-2,000 stb/d and Pf Plot P versus Q wf 2. Construct TPR curves 1,500 psi Tubing Size (inch) Rate THP (BOPD) (psi) Actual depth(fl) Depth TotalEquivalent Pwt Equivalent depth (It) (psi) to THPCftl 4 1000 300 5000 3346 8346 1720 2000 300 5000 2600 7600 1630 3000 300 5000 2800 7800 1723 3 1000 300 5000 2964 7964 1738 2000 300 5000 2400 7400 1770 3000 300 5000 1960 6960 1815
Example 4 A decision has to be made on whether touse 3 in. or 4 in. ID tubing for a well with the following conditions: Steady state inflow Solution; Initial pressure PI Bubble point pressure Depth (TVD) Required THP GOR 2,500 psi 2.0 STB/psi 1,200 psi 5,000 ft 300 psi 200 SCF/bbl (i) Calculate the flow capacity of the well for 4 in. and 3 in. ID use the attached gradient curves (ii) Comment on the general sizing of the available tubing strings. 1. Plot the IPR BHP: = 2500 psi IPR must pass through: Q-2,000 stb/d and Pf Plot P versus Q wf 2. Construct TPR curves 1,500 psi Tubing Size (inch) Rate THP (BOPD) (psi) Actual depth(fl) Depth TotalEquivalent Pwt Equivalent depth (It) (psi) to THPCftl 4 1000 300 5000 3346 8346 1720 2000 300 5000 2600 7600 1630 3000 300 5000 2800 7800 1723 3 1000 300 5000 2964 7964 1738 2000 300 5000 2400 7400 1770 3000 300 5000 1960 6960 1815
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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