The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1000 and the standard deviation is Ş50. 850 900 950 1000 1050 1100 1150 Distribution of Prices What is the approximate percentage of buyers who paid more than $1100? What is the approximate percentage of buyers who paid between $950 and $1000? What is the approximate percentage of buyers who paid between $1000 and $1150?

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The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1000 and the standard deviation is $50.

![Normal Distribution Graph](image_link)

This graph plots the distribution of prices along the x-axis, which ranges from $850 to $1150. The peak of the bell curve is at the mean price of $1000, indicating that this is the most common price paid. As we move away from the mean, the frequency of prices decreases symmetrically on both sides.

**Questions:**

1. **What is the approximate percentage of buyers who paid more than $1100?**
   ```
   __________ %
   ```

2. **What is the approximate percentage of buyers who paid between $950 and $1000?**
   ```
   __________ %
   ```

3. **What is the approximate percentage of buyers who paid between $1000 and $1150?**
   ```
   __________ %
   ```

4. **What is the approximate percentage of buyers who paid between $950 and $1050?**
   ```
   __________ %
   ```

5. **What is the approximate percentage of buyers who paid between $1000 and $1100?**
   ```
   __________ %
   ```

6. **What is the approximate percentage of buyers who paid more than $1150?**
   ```
   __________ %
   ```

### Explanation of the Graph:

- **Y-Axis:** Represents the frequency or probability of occurrence of the prices.
- **X-Axis:** Represents the different prices paid ranging from $850 to $1150.
- **Bell Curve:** Represents the normal distribution of the prices with the highest point at the mean price of $1000. This curve is symmetrical around the mean, with prices becoming less frequent as they move further away from the mean in either direction.

Understanding this graph helps in analyzing the percentage of buyers within certain price ranges, which is essential for making business decisions and understanding consumer behavior.
Transcribed Image Text:The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1000 and the standard deviation is $50. ![Normal Distribution Graph](image_link) This graph plots the distribution of prices along the x-axis, which ranges from $850 to $1150. The peak of the bell curve is at the mean price of $1000, indicating that this is the most common price paid. As we move away from the mean, the frequency of prices decreases symmetrically on both sides. **Questions:** 1. **What is the approximate percentage of buyers who paid more than $1100?** ``` __________ % ``` 2. **What is the approximate percentage of buyers who paid between $950 and $1000?** ``` __________ % ``` 3. **What is the approximate percentage of buyers who paid between $1000 and $1150?** ``` __________ % ``` 4. **What is the approximate percentage of buyers who paid between $950 and $1050?** ``` __________ % ``` 5. **What is the approximate percentage of buyers who paid between $1000 and $1100?** ``` __________ % ``` 6. **What is the approximate percentage of buyers who paid more than $1150?** ``` __________ % ``` ### Explanation of the Graph: - **Y-Axis:** Represents the frequency or probability of occurrence of the prices. - **X-Axis:** Represents the different prices paid ranging from $850 to $1150. - **Bell Curve:** Represents the normal distribution of the prices with the highest point at the mean price of $1000. This curve is symmetrical around the mean, with prices becoming less frequent as they move further away from the mean in either direction. Understanding this graph helps in analyzing the percentage of buyers within certain price ranges, which is essential for making business decisions and understanding consumer behavior.
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