The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1000 and the standard deviation is $70.### Graph ExplanationThe graph represents a bell curve (normal distribution) with the following key points on the x-axis, which denotes the "Distribution of Prices":- 790- 860- 930- 1000 (mean)- 1070- 1140- 1210### Questions and Answers1. **What is the approximate percentage of buyers who paid between $790 and $1000?** - Answer provided: 49.865% ✔️2. **What is the approximate percentage of buyers who paid between $1000 and $1070?** - Answer provided: 34.134% ❌3. **What is the approximate percentage of buyers who paid between $860 and $1000?** - Answer provided: 47.725% ❌4. **What is the approximate percentage of buyers who paid more than $1140?** - Answer provided: 2.275% ❌5. **What is the approximate percentage of buyers who paid between $930 and $1070?** - Answer provided: 68.268% ❌6. **What is the approximate percentage of buyers who paid less than $790?** - Answer provided: 0.135% ❌These questions test your understanding of the normal distribution and your ability to interpret the curve in terms of standard deviations from the mean.

Hi! Thanks for posting the question. Since there are more than three sub-part questions, we will answer first three sub-part questions for you, as per our guidelines. If you want any specific sub-part question to be answered, please re-post the question and mention the sub-part number in the question, for which you need answer. Given: Mean, μ=$1000 Population standard deviation, σ=$70 The z-score is given by, z=x-μσP(790<X<1000)=P790-100070<Z<1000-100070 =P-3<Z<0 =P(Z<0)-P(Z<-3) =0.5 -0.0013 Using Excel formula"=NORM.S.DIST(-3,TRUE)"=0.0013Using Excel formula"=NORM.S.DIST(0,TRUE)"=0.5P(790<X<1000)=0.4987 Therefore, the approximate percentage of buyers who paid between $790 and $1000 is 49.87%P(1000<X<1070)=P1000-100070<Z<1070-100070 =P0<Z<1 =P(Z<1)-P(Z<0) =0.8413 -0.5 Using Excel formula"=NORM.S.DIST(1,TRUE)"=0.8413Using Excel formula"=NORM.S.DIST(0,TRUE)"=0.5P(1000<X<1070)=0.3413 Therefore, the approximate percentage of buyers who paid between $1000 and $1070 is 34.13%P(860<X<1000)=P860-100070<Z<1000-100070 =P-2<Z<0 =P(Z<0)-P(Z<-2) =0.5 -0.0228 Using Excel formula"=NORM.S.DIST(0,TRUE)"=0.5Using Excel formula"=NORM.S.DIST(-2,TRUE)"=0.0228P(860<X<1000)=0.4772 Therefore, the approximate percentage of buyers who paid between $860 and $1000 is 47.72%

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Probability

The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1000 and the standard deviation is $70. 790 860 930 1000 1070 1140 1210 Distribution of Prices What is the approximate percentage of buyers who paid between $790 and $1000? 49.865 What is the approximate percentage of buyers who paid between $1000 and $1070? 34.134

The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1000 and the standard deviation is $70. 790 860 930 1000 1070 1140 1210 Distribution of Prices What is the approximate percentage of buyers who paid between $790 and $1000? 49.865 What is the approximate percentage of buyers who paid between $1000 and $1070? 34.134

A First Course in Probability (10th Edition)

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Author:Sheldon Ross

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Chapter1: Combinatorial Analysis

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Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1000 and the standard deviation is $70.

### Graph Explanation
The graph represents a bell curve (normal distribution) with the following key points on the x-axis, which denotes the "Distribution of Prices":
- 790
- 860
- 930
- 1000 (mean)
- 1070
- 1140
- 1210

### Questions and Answers
1. **What is the approximate percentage of buyers who paid between $790 and $1000?**
- Answer provided: 49.865% ✔️

2. **What is the approximate percentage of buyers who paid between $1000 and $1070?**
- Answer provided: 34.134% ❌

3. **What is the approximate percentage of buyers who paid between $860 and $1000?**
- Answer provided: 47.725% ❌

4. **What is the approximate percentage of buyers who paid more than $1140?**
- Answer provided: 2.275% ❌

5. **What is the approximate percentage of buyers who paid between $930 and $1070?**
- Answer provided: 68.268% ❌

6. **What is the approximate percentage of buyers who paid less than $790?**
- Answer provided: 0.135% ❌

These questions test your understanding of the normal distribution and your ability to interpret the curve in terms of standard deviations from the mean.

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