The graph shows the distribution of the number of textWhat percentage of young adults send between 68 andmessages young adults send per day. The distributionis approximately Normal, with a mean of 128 messages158 text messages per day?34%and a standard deviation of 30 messages.47.5%Daily Text Messaging81.5%95%8 386898128158188218 248

Given,mean(μ)=128standard deviation(σ)=30

Answered: The graph shows the distribution of the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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(a) Show that C = 4/π.(b) Construct the Neumann method, find the expected number of trials (per one acceptance), and find the computational cost (efficiency).
find the mean of the data summarized in the given frequency distribution. Age (yr) of Best Actor frequency When Oscar Was Won 20--29 1 30--39 28 40—49 36 50--59 15 60—69 6 70--79 1
The height (in inches) of a random sample of players in NCAA Division 1 basketball teams is shown to the left. x 75 80 75 87 77 77 67 83 77 80 73 82 73 71 80 76 72 78 68 74 74 72 76 86 77 77 78 12 The height of the shortest player deviates from the mean height by _______ standard deviations. a -2.11 b -1.99 c -1.88 d -1.77
The height (in inches) of a random sample of players in NCAA Division 1 basketball teams is shown to the left. x 75 80 75 87 77 77 67 83 77 80 73 82 73 71 80 76 72 78 68 74 74 72 76 86 77 77 78 13 The height of the tallest player deviates from the mean height by _______ standard deviations. a 2.34 b 2.21 c 2.08 d 1.96
Construct the cumulative frequency distribution for the given data. Age (years) of Best Actress when award was won Cumulative Frequency Age (years) of Best Actress when award was won 20-29 Frequency 26 Less than 30 Less than 40 30-39 33 40-49 50-59 15 Less than 50 3 Less than 60 60-69 7 70-79 Less than 70 80-89 1 Less than 80 Less than 90
Which data set would give the smallest standard deviation? Select one: a. {100, 150, 200, 250, 300} O b. {1, 5, 7, 150, 2} O c. {4, 20, 55, 100, 2} O d. (56, 20, 34, 102, 30}
Using your calculator, find the range and standard deviation, round to two decimals places:The table below gives the number of hours spent watching TV last week by a sample of 24 children. 71 23 53 59 75 72 34 26 52 78 38 50 65 83 54 87 60 84 23 83 90 28 94 10 Range = Standard Deviation =
1. Box Office Revenues The data shown represent the box office total revenue (in millions of dollars) for a randomly selected sample of the top-grossing films in 2009. Check for normality. 37 32 155 277 146 80 66 113 71 29 166 36 28 72 32 32 30 32 52 84 37 402 42 109
Suppose that a histogram is constructed for the frequency distribution shown below.
Exam Grade 55 91 88 188 33 98 78 170 59 88 10 Given the above data set, what is the sample standard deviation of Study hours using a sample of the following students (Student Numbers: 1,3,5,9). Round to the nearest hundredth. Student # 11 2 3 14 5600 7 Study Hours 42 22 24 19 51 11 22 9 39
A group of friends get together every Sunday for a little pick-up hockey. The age of the 20 regulars is shown below. 21 25 26 46 28 22 42 38 22 38 49 44 55 33 45 31 24 43 25 37 Find the mean, median, and mode for the distribution (ungrouped data). Which measure best describes these data? Explain. Group these data into six intervals and produce a frequency table. Determine the mean, and median for a new set of grouped data.
Approximate the mean of the frequency distribution for the ages of the residents of a town. Age Frequency 0-9 31 10-19 27 20-29 14 30-39 20 40-49 22 50-59 43 60-69 46 70-79 11 80-89 7 What is the approximate mean age in years.

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