The graph illustrates a normal distribution for the prices paid for a particular model of HD television. Themean price paid is $1400 and the standard deviation is $70.1190126013301400147015401610Distribution of PricesWhat is the approximate percentage of buyers who paid more than $1540?What is the approximate percentage of buyers who paid between $1400 and $1610?What is the approximate percentage of buyers who paid less than $1190?What is the approximate percentage of buyers who paid between $1330 and $1470?What is the approximate percentage of buyers who paid between $1400 and $1470?What is the approximate percentage of buyers who paid between $1400 and $1540?

Given that: u = $ 1400 Standard deviation = $ 700 By using standard normal distribution. We solve…

Answered: The graph illustrates a normal…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Complete the frequency distribution shown below.
Solve the problem.Suppose that the mean salary in a particular profession is $45,000 with a standard deviation of $2,000. To what percentile does a salary of $48,000 correspond?
Only e and f
Here are data on the monthly price of gas for a certain year, which is a component of the Consumer Price Index. Find the lag2 version of the prices. Month Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Deco Price 2.343 2.326 2.415 2.791 2.968 2.935 3.074 3.018 2.639 2.329 2.284 2.362 Give the lag2 version of the price for each month. Month Jan Feb Mar Price Month Price (Type integers or decimals.) Jul Aug Sep Apr Oct May Nov Jun Dec
Fitting a straight line to a set of data yields the following prediction line. Predict the mean value of Y for x=5
The graph illustrates the distribution of test scores taken by College Algebra students. The maximum possible score on the test was 130, while the mean score was 80 and the standard deviation was 10. 50 60 70 80 90 100 110 Distribution of Test Scores What is the approximate percentage of students who scored between 70 and 80? 34 What is the approximate percentage of students who scored between 60 and 100 on the test? 95 What is the approximate percentage of students who scored between 80 and 110 on the test? 49.85 What is the approximate percentage of students who scored higher than 100 on the test?
(See photo ) The data set on the left represents the annual rate of return (in percent) of eight randomly sampled bond mutual funds, and the data set on the right represents the annual rate of return (in percent) of eight randomly sampled stock mutual funds. The coefficient of variation, CV, is defined as the ratio of the standard deviation to the mean of a data set, so CV = standard deviation/mean The coefficient of variation is unitless and allows for comparison in spread between two data sets by describing the amount of spread per unit mean. After all, larger numbers will likely have a larger standard deviation simply due to the size of the numbers. Compute the coefficient of variation for both data sets. Which data set do you believe has more “spread?”
To test for normality, an ogive of a set of data can be drawn on probability paper. An ogive is a line graph of a cumulative frequency or cumulative relative frequency distribution. Note the probability plot below. Probability Plot Normal 99 95 90 80 70 60 50 30 20 10 5 I 0 5 10 15 Data values 20 ↑ If the ordered pair points (data value, cumulative probability) follow fairly closely to the sketched straight line, the set of data can be considered approximately normally distributed. Part 1 of 3 Note how the vertical scale on the probability plot is not uniform. How does that correspond to a normal distribution? This answer has not been graded yet. Percent ▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
Find the standard deviation of the data summarized in the given frequency distribution. The manager of a bank recorded the amount of time each customer spent waiting in line during peak business hours one Monday. The frequency distribution below summarizes the results. Find the standard deviation. Round your answer to one decimal place. Waiting time Number of (minutes) customer 1.5 9 15 12 11 0 3 5.5 9.5 13.5 17.5 21.5
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1000 and the standard deviation is $70. Round answers for part 1 and 2 to at least 4 decimal places, and the answer for part 3 to at least 2 decimal place. Use technology.7908609301000107011401210 What price would the buyer pay to get 8% the most expensive HD televisions?
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1200 and the standard deviation is $75. 975 1050 1125 1200 1275 1350 1425 Distribution of Prices What is the approximate percentage of buyers who paid between $1200 and $1425? 49.85 ✔% What is the approximate percentage of buyers who paid more than $1350? %
The approximate mean age is years. (Round to one decimal place as needed.) Approximate the mean of the frequency distribution for the ages of the residents of a town. Age Frequency 0-9 37 10-19 22 20-29 10 30-39 30 40-49 17 50-59 54 60-69 43 70-79 16 80-89 9

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