The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34

The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34

EBK JAVA PROGRAMMING

9th Edition

ISBN:9781337671385

Author:FARRELL

Publisher:FARRELL

Chapter12: Exception Handling

Section: Chapter Questions

Problem 20RQ

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The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34
please help me using python
Java programming See attached The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catch statement to catch java.util.InputMismatchException, and output 0 for the age. import java.util.Scanner;import java.util.InputMismatchException; public class NameAgeChecker { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); String inputName; int age; inputName = scnr.next(); while (!inputName.equals("-1")) { // FIXME: The following line will throw an InputMismatchException. // Insert a try/catch statement to catch the exception. age = scnr.nextInt(); System.out.println(inputName + " " + (age + 1)); inputName = scnr.next(); } }}
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catch statement to catch java.util.InputMismatchException, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 NameAgeChecker.java import java.util.Scanner;import java.util.InputMismatchException; public class NameAgeChecker {public static void main(String[] args) {Scanner scnr = new Scanner(System.in); String inputName;int age;inputName = scnr.next();while (!inputName.equals("-1")) {// FIXME: The following line will throw an InputMismatchException.// Insert a try/catch statement to catch the exception.age = scnr.nextInt();System.out.println(inputName + " " + (age + 1));inputName = scnr.next();}}}
Subject: Object Oriented PrgrammingLanguage: Java ProgramTopic: Exception (SEE ATTACHED PHOTO FOR THE PROBLEM)
The while loop reads values from input until an integer is read. Complete the exception handler in the while loop to catch an InputMismatchException exception and: Output "Removed unacceptable input for number of cents". End with a newline. Discard the invalid input. Ex: If the input is 20 60, then the output is: 20 cents = 4 nickels Processed one valid input value Ex: If the input is Aya Tia 20 60, then the output is: New JAVA code can only be added after code given: Removed unacceptable input for number of cents Removed unacceptable input for number of cents 20 cents = 4 nickels Processed one valid input value Note: Each value read from input is on one line. /******************************************************************************************************* New Java Code here: test input: Aya Tia 20 60 *******************************************************************************************************/
s and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 419894.2696446.qx3zqy7 #include <string>#include <iostream> using namespace std; int main() { string inputName; int age; // Set exception mask for cin stream cin.exceptions(ios::failbit); cin >> inputName; while(inputName != "-1") { // FIXME: The following line will throw an ios_base::failure. // Insert a try/catch statement to catch the exception. // Clear cin's failbit to put cin in a useable state. cin >> age; cout << inputName << " " << (age + 1) << endl; cin >> inputName; } return 0;}
PYTHON PROGRAMMING Write a function that takes a single number as an argument: 1) This function should then check whether a number is an even number (2,4,6,8) and raise an exception if otherwise 2) Call this function with an uneven number first without catching the exception and then with catching the exception and printing a warning to the user afterwards
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What happens if an exception is thrown, but not caught?
PYTHON: A pedometer treats walking 2,000 steps as walking 1 mile. Write a steps_to_miles() function that takes the number of steps as a parameter and returns the miles walked. The steps_to_miles() function throws a ValueError object with the message "Exception: Negative step count entered." when the number of steps is negative. Complete the main() program that reads the number of steps from a user, calls the steps_to_miles() function, and outputs the returned value from the steps_to_miles() function. Use a try-except block to catch any ValueError object thrown by the steps_to_miles() function and output the exception message. Output each floating-point value with two digits after the decimal point, which can be achieved as follows:print('{:.2f}'.format(your_value)) Ex: If the input of the program is: 5345 the output of the program is: 2.67 Ex: If the input of the program is: -3850 the output of the program is: Exception: Negative step count entered.
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