new java code can only be added after line 17. The while loop reads values from input until an integer is read. Complete the exception handler in the while loop to catch an InputMismatchException exception and:- Output "Removed unacceptable input for number of cents". End with a newline.- Discard the invalid input.Ex: If the input is 20 60, then the output is:```20 cents = 4 nickelsProcessed one valid input value```Ex: If the input is Aya Tia 20 60, then the output is:```Removed unacceptable input for number of centsRemoved unacceptable input for number of cents20 cents = 4 nickelsProcessed one valid input value```Note: Each value read from input is on one line.```javaimport java.util.Scanner;import java.util.InputMismatchException;public class Cents { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int numCents; boolean valueFound = false; while (!valueFound) { try { numCents = scnr.nextInt(); valueFound = true; System.out.println(numCents + " cents = " + (numCents / 5) + " nickels"); System.out.println("Processed one valid input value"); } } }}```

Answered: The while loop reads values from input…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

new java code can only be added after line 17.

The while loop reads values from input until an integer is read. Complete the exception handler in the while loop to catch an InputMismatchException exception and:

- Output "Removed unacceptable input for number of cents". End with a newline.
- Discard the invalid input.

Ex: If the input is 20 60, then the output is:

```
20 cents = 4 nickels
Processed one valid input value
```

Ex: If the input is Aya Tia 20 60, then the output is:

```
Removed unacceptable input for number of cents
Removed unacceptable input for number of cents
20 cents = 4 nickels
Processed one valid input value
```

Note: Each value read from input is on one line.

```java
import java.util.Scanner;
import java.util.InputMismatchException;

public class Cents {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int numCents;
boolean valueFound = false;

while (!valueFound) {
try {
numCents = scnr.nextInt();
valueFound = true;
System.out.println(numCents + " cents = " + (numCents / 5) + " nickels");
System.out.println("Processed one valid input value");
}
}
}
}
```

Expert Solution

Step 1: Providing the algorithm

1. Start
2. Initialize Scanner object scnr to read input from the user.
3. Declare an integer variable numCents and a boolean variable valueFound, both initially set to false.
4. Enter a while loop with condition !valueFound to repeatedly prompt for input until a valid input is provided.
a. Inside the loop:
i. Try to read an integer from the user using scnr.nextInt().
ii. If no exception occurs, set valueFound to true.
- Print numCents + " cents = " + (numCents / 5) + " nickels"
- Print "Processed one valid input value"
iii. If an InputMismatchException occurs:
- Print "Removed unacceptable input for number of cents"
- Discard the invalid input using scnr.nextLine()
5. End

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