The general solution of (D²+2D+1)(D²+4)y=0 @ -+Ceª A y=(C,+Cx)e*+C;e B none of the given choices © y=(c,+Cx)e*+C+c¢* -2x D y=(C,+Cr)e=+C,cos2r + C sin2x ® y=(C,+Cx)e*+C,cos2r + C ,sin2x

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The general solution of (D²+2D +1)(D²+4)y=0 is
B none of the given choices
© y=(c,+c)e*+ce-"+C¢"
D y=(C,+Cx)e=*+C,cos2x + C sin2x
y=(C,+Cx)e*+C,cos2r + C ,sin2x
Transcribed Image Text:The general solution of (D²+2D +1)(D²+4)y=0 is B none of the given choices © y=(c,+c)e*+ce-"+C¢" D y=(C,+Cx)e=*+C,cos2x + C sin2x y=(C,+Cx)e*+C,cos2r + C ,sin2x
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