а) у%3DIn(x? + 4)(2х + 5) b) у%3DIn (12х - 7) с) у ex2+3 ex-4 - d) y= 2x'ex e) y = ev3x+T

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.2: Exponents And Radicals
Problem 23E
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а) у%3DIn(x? + 4)(2х + 5)
b) у%3DIn (12х - 7)
с) у
ex2+3
ex-4
-
d) y= 2x'ex
e) y = ev3x+T
Transcribed Image Text:а) у%3DIn(x? + 4)(2х + 5) b) у%3DIn (12х - 7) с) у ex2+3 ex-4 - d) y= 2x'ex e) y = ev3x+T
Expert Solution
Step 1

Given data:

 

a)

The given function is: y=ln(x2+4)(2x+5).

 

The expression for derivative of the given function is,

Calculus homework question answer, step 1, image 1

Apply the product rule.

Calculus homework question answer, step 1, image 2

Thus, the derivative of the given function is ln(x2+4)2+(4x2+10x)/(x2+4).

Step 2

Given data:

 

b)

The given function is: y=ln(12x-7).

 

The expression for the derivative of the given function with the help of chain rule is,

Calculus homework question answer, step 2, image 1

Thus, the derivative of the given function is 12/(12x-7).

Step 3

c)

The given function is: y=(ex^2+3)/ex-4.

 

Take the logarithm on both sides of the given function.

Calculus homework question answer, step 3, image 1

Differentiate the above expression with respect to x.

Calculus homework question answer, step 3, image 2

Substitute the value of y in the above expression.

Calculus homework question answer, step 3, image 3

Thus, the differentiation of the given expression is ( ex^2+3)(2x-1)/ex-4.

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