Solve for x (х+3)^2 О х^2 + 3x + 2 О 2х^2 + 3x + 2 О х^2 + 6х + 2 О х^2 + 6х + 9

Q: no real solution z= -8 z= -7 z = -6 z = -5 z = -4 z = -3 z = -2 z = -1 z = 0 z = 1 z= 2 z = 3 z = 4…

A: Solve 0=z^2-10z+25 by factoring.

Q: If x^4+ax^2+bx+c= 0 has roots x=−1,2,and 3, find the values of a, b,and c, as well as the fourth…

A:

Q: For the quadratic equation 9x^2+(3k+1)x+4=0 find the value(s) of k so that there is 1 real root.

A:

Q: 2х - 3 Зх - 5 4. Simplify2 - Зх — _3x- 4 x2-8x +16 - 8x16 х

A: Given,

Q: Solve the equation. Make sure to check for extraneous solutions A) 4x^2-5= 2^9x+1 B) 3^x= 9^-x+5…

A: see below the answer and calculation

Q: Simplify (-4x^2-8x+7)+(12x-9)-(7x+2)^2 and write in standard form.

A: To simplify -4x2-8x+7+12x-9-7x+22 and to write in standard form.

Q: Find an equation in the form ax^2 + bx + c = 0 with roots 4 and -7/6

A: The equation is : 6x² - 17x - 28 = 0   The detailed explanation is as follows below:

Q: X^-2 - X^-1 -12 =0

A:

Q: Solve for x. -8 -14 x-3

A:

Q: Rationalize the denominator of 5/(square root of 14) - 2

A: We need to rationalize the denominator of

Q: show that the equation x^5+2x^3+3x-4=0 has exactly one root. Justify your answer.

A: Given equation has only one root. Here is its explanation.

Q: X1 Х2 X3 Х4 ☐☐☐☐ ts X1 +X2 X1 X2 +X3 X3 00 +X4 +X4 -4 -4 4 4

A: The objective is to solve the above question.

Q: identify all of the complex zeros of the function 2x^(4)-12x^(3)+12x^(2)-23x+12

A: Solution is given below in step 2.

Q: n-1 (+55)^-(1-13)" (1+55) - (1-J5)n-) 25 2n- 5

A:

Q: Simplify (-4x^2-8x+7)+(12x-9)-(7x+2)^2 and write in standard form. Solve exactly like the example…

A: To simplify -4x2-8x+7+12x-9-7x+22 and to write in standard form.