The gas-phase decomposition of NOBr has a k= 0.82 M¹ s1 at 10°C.NOBr(g) → NO(g) + ½ Br₂ (g) rate k[ NOBr]²We start with 0.074 M NOBr in a flask at 10°C.17TA. How long (in secs) does it take to use up 0.011 M of this NOBr? Only enter the number with nounits2.4

As the unit of rate constant is M-1.s-1 ,the reaction is second order.

The gas-phase decomposition of NOBr has a k= 0.82 M1 s1¹ at 10°C. NOBr(g) → NO(g) + ½ Br₂ (g) rate k[ NOBr]² - We start with 0.074 M NOBr in a flask at 10°C. A. How long (in secs) does it take to use up 0.011 M of this NOBr? Only enter the number with no units 2.4

The gas-phase decomposition of NOBr has a k= 0.82 M1 s1¹ at 10°C. NOBr(g) → NO(g) + ½ Br₂ (g) rate k[ NOBr]² - We start with 0.074 M NOBr in a flask at 10°C. A. How long (in secs) does it take to use up 0.011 M of this NOBr? Only enter the number with no units 2.4

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The gas-phase decomposition of NOBr has a k= 0.82 M¹ s1 at 10°C.
NOBr(g) → NO(g) + ½ Br₂ (g) rate k[ NOBr]²
We start with 0.074 M NOBr in a flask at 10°C.
17T
A. How long (in secs) does it take to use up 0.011 M of this NOBr? Only enter the number with no
units
2.4

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