The functions y1(t) = t² and y2(t) = t³ are solutions of the homogeneous differential equation ty" – 4ty' + on (0, o0). To find a solution of the nonhomogeneous differential equation t2y" – 4ty' + 6y = 4t³ on (0, 00) the function u(t) of yp = u1(t)t² + uz(t)t³? %3D %3D Lütfen birini seçin: O 4 -4t -4t2
The functions y1(t) = t² and y2(t) = t³ are solutions of the homogeneous differential equation ty" – 4ty' + on (0, o0). To find a solution of the nonhomogeneous differential equation t2y" – 4ty' + 6y = 4t³ on (0, 00) the function u(t) of yp = u1(t)t² + uz(t)t³? %3D %3D Lütfen birini seçin: O 4 -4t -4t2
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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