Use variation of parameters to find a general solution to the differential equation given that the functions y₁ and y2 are linearly independent solutions to the corresponding homogeneous equation for t> 0. ty" (t+1)y'+y=231²; Y₁ = e², y₂ =1+1 Set up the particular solution yp (t) = v₁ (t)y₁ (t) + v2(t)y2(t) to the nonhomogeneous equation by substituting in two linearly independent solutions (y₁ (t), y2(t)} to the corresponding homogenous equation. Yp(t)= ☐

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Use variation of parameters to find a general solution to the differential equation given that the functions y₁ and y2 are
linearly independent solutions to the corresponding homogeneous equation for t> 0.
ty" (t+1)y+y=23t²;
Y₁ = e², y₂ =1+1
Set up the particular solution yp (t) = v₁ (t)y₁ (t) + v2(t)y2(t) to the nonhomogeneous equation by substituting in two linearly
independent solutions (y₁ (t), y2(t)} to the corresponding homogenous equation.
Yp(t)= ☐
Transcribed Image Text:Use variation of parameters to find a general solution to the differential equation given that the functions y₁ and y2 are linearly independent solutions to the corresponding homogeneous equation for t> 0. ty" (t+1)y+y=23t²; Y₁ = e², y₂ =1+1 Set up the particular solution yp (t) = v₁ (t)y₁ (t) + v2(t)y2(t) to the nonhomogeneous equation by substituting in two linearly independent solutions (y₁ (t), y2(t)} to the corresponding homogenous equation. Yp(t)= ☐
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