Consider solving the differential equation y" + 2y' – 3y = 4e' by the method of variation of parameters. The Wronskian of the fundamental solutions y1 and yY2 of the homogeneous equation, the particular solution Yp and the general solution are Select one: O W y1, y2] = -4e-#, yp = (t – † )e² and y = ce + cze¬3t + tet O W [y1, y2] = -4e-#, yp = (t + †)ef and y = ceʻ + cze¯t + te O W [y1,y2] – de ª, yp = (÷ – t)e² and y = cqe' + cze t – te' --4e O W y1, y2] = 4e-ª, yp = -(t+ +)e and y = cje' + c2e¬# – te