Match the solution curve with one of the differential equations. Where y" + 2y' + 2y = 0 y" + y = 0 y" + 16y = 0 y" + 2y' + y = 0 y" - 3y' 4y = 0 Oy" - 6y' + 8y = 0 Explain your reasoning. (Assume that k, k₁, and Kk₂ are all positive.) The auxiliary equation should have a pair of complex roots a ± ßi where a < 0, so that the solution has the form ex (C₁ cos(x) + C₂ sin(x)). The auxiliary equation should have two positive roots, so that the solution has the form c₁ek1x + c₂ek2x. The auxiliary equation should have one positive and one negative root, so that the solution has the form c₁ek₁x + ₂е-k₂. e-kx + c₂xe-kx. The auxiliary equation should have a repeated negative root, so that the solution has the form c₁e The differential equation should have the form y" + k²y = 0 where k = 1 so that the period of the solution is 2π. k²y The differential equation should have the form y" + = 0 where k = 2 so that the period of the solution is 7.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Match the solution curve with one of the differential equations.
When
y" + 2y' + 2y = 0
y" + y = 0
y" + 16y = 0
y" + 2y' + y = 0
Oy" 3y' - 4y = 0
Oy" - 6y' + 8y = 0
Explain your reasoning. (Assume that k, k₁, and k₂ are all positive.)
The auxiliary equation should have a pair of complex roots a ± ßi where a < 0, so that the solution has the form
ex (C₁ cos(x) + C₂: sin (3x)).
The auxiliary equation should have two positive roots, so that the solution has the form c₁ek₁x + c₂e₂x.
1x
The auxiliary equation should have one positive and one negative root, so that the solution has the form c₁ek₁x + ₂е-k₂.
The auxiliary equation should have a repeated negative root, so that the solution has the form c₁e-kx + ₂xe-kx.
The differential equation should have the form y" + k²y = 0 where k = 1 so that the period of the solution is 2π.
The differential equation should have the form y" + k²y = 0 where k = 2 so that the period of the solution is T.
Transcribed Image Text:Match the solution curve with one of the differential equations. When y" + 2y' + 2y = 0 y" + y = 0 y" + 16y = 0 y" + 2y' + y = 0 Oy" 3y' - 4y = 0 Oy" - 6y' + 8y = 0 Explain your reasoning. (Assume that k, k₁, and k₂ are all positive.) The auxiliary equation should have a pair of complex roots a ± ßi where a < 0, so that the solution has the form ex (C₁ cos(x) + C₂: sin (3x)). The auxiliary equation should have two positive roots, so that the solution has the form c₁ek₁x + c₂e₂x. 1x The auxiliary equation should have one positive and one negative root, so that the solution has the form c₁ek₁x + ₂е-k₂. The auxiliary equation should have a repeated negative root, so that the solution has the form c₁e-kx + ₂xe-kx. The differential equation should have the form y" + k²y = 0 where k = 1 so that the period of the solution is 2π. The differential equation should have the form y" + k²y = 0 where k = 2 so that the period of the solution is T.
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