The free energy change for the following reaction at 25 °C, when [Cr**]= 2.80×10-3 M and [H*]= 1.11 M, is 94.0 kJ: 2Cr**(2.80x10 M) + H,(g)2Cr*+*(aq) + 2.00H*(1.11 M) AG=94.0 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction?

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The free energy change for the following reaction at 25 °C, when [Cr**]= 2.80×103
M and [H= 1.11 M, is 94.0 kJ:
2Cr*(2.80×10³ M) + H,(g)2Cr*(aq) + 2.00H*(1.11 M)
AG = 94.0 kJ
What is the cell potential for the reaction as written under these conditions?
Answer:
V
Would this reaction be spontaneous in the forward or the reverse direction?
Transcribed Image Text:The free energy change for the following reaction at 25 °C, when [Cr**]= 2.80×103 M and [H= 1.11 M, is 94.0 kJ: 2Cr*(2.80×10³ M) + H,(g)2Cr*(aq) + 2.00H*(1.11 M) AG = 94.0 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction?
The free energy change for the following reaction at 25 °C, when [Pb4*1=1.15 M and
[Fe?+] = 5.40x10-3 M, is -73.9 kJ:
Pb2
(1.15 M) + Fe(s)– Pb(s) + Fe²*(5.40×10 M) AG = -73.9 kJ
What is the cell potential for the reaction as written under these conditions?
Answer:
V
Would this reaction be spontaneous in the forward or the reverse direction?
Transcribed Image Text:The free energy change for the following reaction at 25 °C, when [Pb4*1=1.15 M and [Fe?+] = 5.40x10-3 M, is -73.9 kJ: Pb2 (1.15 M) + Fe(s)– Pb(s) + Fe²*(5.40×10 M) AG = -73.9 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction?
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