The frame is made from uniform rod which has a mass p per unit length. A smooth recessed slot constrains the small rollers at A and B to travel horizontally. Force P is applied to the frame through a cable attached to an adjustable collar C. Determine the magnitudes and directions of the normal forces which act on the rollers if (a) h = 0.25L, (b) h = 0.50L, and (c) h - 0.81L. The forces will be positive if up, negative if down. Evaluate your results for p = 2.5 kg/m, L = 510 mm, and P = 43 N. What is the acceleration of the frame in each case? (a) Answers: (b) L (c) A h- 0.25L: h- 0.50L: h- 0.81L: L A A A ■ B i i i Р N, N, N₁ i i i N₁" N, a N₁ i i m/s m/s m/s

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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### Mechanical Engineering Problem: Determining Forces and Acceleration of a Constrained Frame

#### Problem Statement:
The frame is made from a uniform rod which has a mass \( \rho \) per unit length. A smooth recessed slot constrains the small rollers at \( A \) and \( B \) to travel horizontally. Force \( P \) is applied to the frame through a cable attached to an adjustable collar \( C \). Determine the magnitudes and directions of the normal forces which act on the rollers if:
- \( (a) \, h = 0.25L \)
- \( (b) \, h = 0.50L \)
- \( (c) \, h = 0.81L \)

where \( h \) is the vertical distance of the collar from the bottom roller, and \( L \) is the length of the sides of the square frame.

The forces will be positive if up, negative if down. Evaluate your results for:
- \( \rho = 2.5 \, \text{kg/m} \),
- \( L = 510 \, \text{mm} \),
- \( P = 43 \, \text{N} \).

What is the acceleration of the frame in each case?

#### Diagram Explanation:
There is an illustration of the frame as described:
- The frame forms a square with side length \( L \).
- There are small rollers at points \( A \) and \( B \) at the bottom vertices of the square.
- A cable applies force \( P \) horizontally to the frame through a collar \( C \) located a height \( h \) above the bottom roller \( B \).

#### Answers:
To solve this problem, you need to determine the values for:
- Normal force \( N_A \) at roller \( A \),
- Normal force \( N_B \) at roller \( B \),
- Acceleration \( a \) of the frame in each scenario.

##### When \( h = 0.25L \):
- \(N_A = \) [Your calculated value]
- \(N_B = \) [Your calculated value]
- Acceleration \( a = \) [Your calculated value] m/s\(^2\)

##### When \( h = 0.50L \):
- \(N_A = \) [Your calculated value]
- \(N_B = \) [Your calculated value]
- Acc
Transcribed Image Text:### Mechanical Engineering Problem: Determining Forces and Acceleration of a Constrained Frame #### Problem Statement: The frame is made from a uniform rod which has a mass \( \rho \) per unit length. A smooth recessed slot constrains the small rollers at \( A \) and \( B \) to travel horizontally. Force \( P \) is applied to the frame through a cable attached to an adjustable collar \( C \). Determine the magnitudes and directions of the normal forces which act on the rollers if: - \( (a) \, h = 0.25L \) - \( (b) \, h = 0.50L \) - \( (c) \, h = 0.81L \) where \( h \) is the vertical distance of the collar from the bottom roller, and \( L \) is the length of the sides of the square frame. The forces will be positive if up, negative if down. Evaluate your results for: - \( \rho = 2.5 \, \text{kg/m} \), - \( L = 510 \, \text{mm} \), - \( P = 43 \, \text{N} \). What is the acceleration of the frame in each case? #### Diagram Explanation: There is an illustration of the frame as described: - The frame forms a square with side length \( L \). - There are small rollers at points \( A \) and \( B \) at the bottom vertices of the square. - A cable applies force \( P \) horizontally to the frame through a collar \( C \) located a height \( h \) above the bottom roller \( B \). #### Answers: To solve this problem, you need to determine the values for: - Normal force \( N_A \) at roller \( A \), - Normal force \( N_B \) at roller \( B \), - Acceleration \( a \) of the frame in each scenario. ##### When \( h = 0.25L \): - \(N_A = \) [Your calculated value] - \(N_B = \) [Your calculated value] - Acceleration \( a = \) [Your calculated value] m/s\(^2\) ##### When \( h = 0.50L \): - \(N_A = \) [Your calculated value] - \(N_B = \) [Your calculated value] - Acc
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