The force vector F has a magnitude of F = 460 lb and acts at point A at an angle = 11° with respect to vertical as shown. The force is balanced by the tension forces parallel to the two rods AC and AB such that the vector equation F+ FAC + FAB = 0 is satisfied. Determine the tension forces in the two rods in Cartesian components. b C Ⓒi❀o BY NC SA 2013 Michael Swanbom NF Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value 5.9 ft 2.8 ft 3.1 ft For the component notation, use an 'xy' coordinate system with 'y' poining up and 'x' pointing to the right. 3) lb 3) lb a b с FAC a FAB=

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The force vector F has a magnitude of F = 460 lb and acts at point A at an angle = 11° with respect
to vertical as shown. The force F is balanced by the tension forces parallel to the two rods AC and AB
such that the vector equation F + FAC + FAB 0 is satisfied. Determine the tension forces in the
two rods in Cartesian components.
b
C
(CC) Oo
BY NC SA
2013 Michael Swanbom
a
b
NF
Values for dimensions on the figure are given in the following table. Note the figure may not be to scale.
Variable Value
5.9 ft
2.8 ft
3.1 ft
For the component notation, use an 'xy' coordinate system with 'y' poining up and 'x' pointing to the right.
3) lb
с
FAC
FAB
Submit Question
c'es
c'es
î
+
a
+
=
3) lb
Transcribed Image Text:The force vector F has a magnitude of F = 460 lb and acts at point A at an angle = 11° with respect to vertical as shown. The force F is balanced by the tension forces parallel to the two rods AC and AB such that the vector equation F + FAC + FAB 0 is satisfied. Determine the tension forces in the two rods in Cartesian components. b C (CC) Oo BY NC SA 2013 Michael Swanbom a b NF Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value 5.9 ft 2.8 ft 3.1 ft For the component notation, use an 'xy' coordinate system with 'y' poining up and 'x' pointing to the right. 3) lb с FAC FAB Submit Question c'es c'es î + a + = 3) lb
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