Answer for the 1st part of the problem. magnitude of force A = 74 N direction of force A = 25o north of west second force = P direction of force P = α south of west arrow_forwardThe resultant of two forces is horizontal , it means that the y component of resultant = 0 Ry = ASin(25o) - PSin(α) 0 = (74×0.42) - PSin(α) PSin(α) = 31.08 NFor, the smallest force P , the value of Sinα must be maximum which is 1 when the value of αis 90 degree Thus, P×Sin(90o) = 31.08 N P = 31.08 N The magnitude of smallest force P = 31.08 N the direction of force P = 90 degree south of west = along - y axis= arrow pointing vertically downw Required informationNOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.Two forces are applied as shown to a hook support. The magnitude of A is 74 N.25°DCIf the direction and magnitude of the smallest force P is such that the resultant R of the two forces applied to the support is horizontal,determine the corresponding magnitude of R.The corresponding magnitude of R is [N. Required informationNOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.Two forces are applied as shown to a hook support. The magnitude of A is 74 N.25°DGDetermine by trigonometry the magnitude and direction of the smallest force P for which the resultant R of the two forces applied tothe support is horizontal.The magnitude of the smallest force P is [IN and the direction is: (Click to select)(Click to select)- 11

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Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Answer for the 1st part of the problem.

magnitude of force A = 74 N direction of force A = 25o north of west second force = P direction of force P = α south of west arrow_forward

The resultant of two forces is horizontal , it means that the y component of resultant = 0 Ry = ASin(25o) - PSin(α) 0 = (74×0.42) - PSin(α) PSin(α) = 31.08 NFor, the smallest force P , the value of Sinα must be maximum which is 1 when the value of αis 90 degree Thus, P×Sin(90o) = 31.08 N P = 31.08 N The magnitude of smallest force P = 31.08 N the direction of force P = 90 degree south of west = along - y axis= arrow pointing vertically downw

Required information
NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.
Two forces are applied as shown to a hook support. The magnitude of A is 74 N.
25°
DC
If the direction and magnitude of the smallest force P is such that the resultant R of the two forces applied to the support is horizontal,
determine the corresponding magnitude of R.
The corresponding magnitude of R is [
N.

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