The force F acting on a body with mass m and velocity v is the rate of change of momentum: F = (d/dt)(mv). If m is constant, this becomes F = ma, where a = dv/dt is the acceleration. But in the theory of relativity the mass of a particle varies with v as follows: m= mo/NT- v/c², where mo is the mass of the particle at rest and c is the speed of light. Show that moa F = (1 – v*/c*)/²

The force F acting on a body with mass m and velocity v is the rate of change of momentum: F = (d/dt)(mv). If m is constant, this becomes F = ma, where a = dv/dt is the acceleration. But in the theory of relativity the mass of a particle varies with v as follows: m= mo/NT- v/c², where mo is the mass of the particle at rest and c is the speed of light. Show that moa F = (1 – v/c)/²

Classical Dynamics of Particles and Systems

5th Edition

ISBN:9780534408961

Author:Stephen T. Thornton, Jerry B. Marion

Publisher:Stephen T. Thornton, Jerry B. Marion

Chapter2: Newtonian Mechanics-single Particle

Section: Chapter Questions

Problem 2.50P: According to special relativity, a particle of rest mass m0 accelerated in one dimension by a force...

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